Answer:
(a) ΔU=747J
(b) γ=1.3
Explanation:
For (a) change in internal energy
According to first law of thermodynamics the change in internal energy is given as
ΔU=Q-W
Substitute the given values
ΔU=970J-223J
ΔU=747J
For(b) γ for the gas.
We can calculate γ by ratio of heat capacities of the gas
γ=Cp/Cv
Where Cp is the molar heat capacity at constant pressure
Cv is the molar heat capacity at constant volume
To calculate γ we first need to find Cp and Cv
So
For Cp
As we know
Q=nCpΔT
Cp=(Q/nΔT)
![C_{p}=\frac{970J}{1.75mol*(25^{o}C-10^{o}C )}\\C_{p}=37J/mol.K](https://tex.z-dn.net/?f=C_%7Bp%7D%3D%5Cfrac%7B970J%7D%7B1.75mol%2A%2825%5E%7Bo%7DC-10%5E%7Bo%7DC%20%29%7D%5C%5CC_%7Bp%7D%3D37J%2Fmol.K)
From relation of Cv and Cp we know that
Cp=Cv+R
Where R is gas constant equals to 8.314J/mol.K
So
![C_{v}=C_{p}-R\\C_{v}=37-8.314\\C_{v}=28.687J/mol.K\\](https://tex.z-dn.net/?f=C_%7Bv%7D%3DC_%7Bp%7D-R%5C%5CC_%7Bv%7D%3D37-8.314%5C%5CC_%7Bv%7D%3D28.687J%2Fmol.K%5C%5C)
So
γ=Cp/Cv
γ=[(37J/mol.K) / (28.687J/mol.K)]
γ=1.3
Answer:
Stage one of sleep, also known as the transitional phase, occurs when one finds themselves floating in and out of consciousness. During this NREM stage, you may be partially awake while your mind begins to drift off. This period of drowsiness eventually leads to a light sleep
Explanation:
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