All categories

3 years ago

Which do you think the correct answer was wrong Help plis:(

Physics

1 answer:

Alex777 [14]3 years ago

7 0

Answer:

36255 Kg.

Explanation:

From the question given above, the following data were obtained:

Momentum = 1450200 Kgm/s

Velocity = 40 m/s

Mass =?

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the mass of the train as follow:

Momentum = 1450200 Kgm/s

Velocity = 40 m/s

Mass =?

Momentum = mass × velocity

1450200 = mass × 40

Divide both side by 40

Mass = 1450200 / 40

Mass = 36255 Kg

Thus the mass of the train is 36255 Kg

You might be interested in

Three masses (3 kg, 5 kg, and 7 kg) are located in the xy-plane at the origin, (2.3 m, 0), and (0, 1.5 m), respectively.

Artist 52 [7]

Answer:

a) C.M $=(\bar x, \bar y)=(0.767,0.7)m$

b) $(x_4,y_4)=(-1.917,-1.75)m$

Explanation:

The center of mass "represent the unique point in an object or system which can be used to describe the system's response to external forces and torques"

The center of mass on a two dimensional plane is defined with the following formulas:

$\bar x =\frac{\sum_{i=1}^N m_i x_i}{M}$

$\bar y =\frac{\sum_{i=1}^N m_i y_i}{M}$

Where M represent the sum of all the masses on the system.

And the center of mass C.M $=(\bar x, \bar y)$

Part a

$m_1= 3 kg, m_2=5kg,m_3=7kg$ represent the masses.

$(x_1,y_1)=(0,0),(x_2,y_2)=(2.3,0),(x_3,y_3)=(0,1.5)$ represent the coordinates for the masses with the units on meters.

So we have everything in order to find the center of mass, if we begin with the x coordinate we have:

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)}{3kg+5kg+7kg}=0.767m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)}{3kg+5kg+7kg}=0.7m$

C.M $=(\bar x, \bar y)=(0.767,0.7)m$

Part b

For this case we have an additional mass $m_4=6kg$ and we know that the resulting new center of mass it at the origin C.M $=(\bar x, \bar y)=(0,0)m$ and we want to find the location for this new particle. Let the coordinates for this new particle given by (a,b)

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)}{3kg+5kg+7kg+6kg}=0m$

If we solve for a we got:

$(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)=0$

$a=-\frac{(5kg*2.3m)}{6kg}=-1.917m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)}{3kg+5kg+7kg+6kg}=0m$

$(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)=0$

And solving for b we got:

$b=-\frac{(7kg*1.5m)}{6kg}=-1.75m$

So the coordinates for this new particle are:

$(x_4,y_4)=(-1.917,-1.75)m$

5 0

3 years ago

Science: Physics AND Biology - Please help me with these, it's due tonight.

Ostrovityanka [42]

The answer to the first question is that plants make glucose and oxygen by taking in CO2 and H20.

The answer to the second question is having a heavier mass increases the force of a moving object. That is the Second Law of Motion, F = ma.

7 0

3 years ago

Explian the construction of electric motor?

Nataly_w [17]

Answer:

Hope the above picture might help you :)

7 0

3 years ago

Benny wants to estimate the mean lifetime of Energizer batteries, with a confidence level of 97%, and with a margin of error not

VikaD [51]

Answer:

143 batteries does Benny need to sample

Explanation:

Given data

confidence level = 97%

error = ±10 hours

standard deviation SD = 55 hours

to find out

how many batteries does Benny need to sample

solution

confidence level is 97%

so a will be 1 - 0.97 = 0.03

the value of Z will be for a 0.03 is 2.17 from standard table

so now we calculate no of sample i.e

no of sample = (Z× SD/ error)²

no of sample = (2.16 × 55 / 10)²

no of sample = 142.44

so 143 batteries does Benny need to sample

7 0

3 years ago

Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0.25 m /

Blizzard [7]

Answer:

0.28 that is for the 25 and for 50 is 0.56

Explanation:

7 0

3 years ago

Read 2 more answers