1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Drupady [299]
3 years ago
6

PLS HELP ASAP!! I will do brainliest!!!! PLS IMMA DIE

Chemistry
2 answers:
valina [46]3 years ago
4 0
B. Combination of all wavelengths of visible light
Bess [88]3 years ago
3 0
B. combination of all wavelengths of visible light
You might be interested in
The density of copper is 8.9 g/mL. What is the volume of 20.5 g copper?
love history [14]

Answer:

density = 8.9 g/ml

m = 20.5 g

V = ... ?

density = m/V

V = m / density

= 20.5 / 8.9

= 2.30337 ml

3 0
3 years ago
5. Why doesn't the air at a frontal boundary mix?​
Vsevolod [243]

Answer:

At a front, the two air masses have different densities, based on temperature, and do not easily mix. One air mass is lifted above the other, creating a low pressure zone.

Explanation:

Hope this helps!

4 0
2 years ago
What is the variable that is changed by
denpristay [2]

Answer:

b. independent/manipulated variable

Explanation:

Independent/manipulated variable - refers to the variable that is changed by the scientist or an experimenter. Only one variable that is independent is required to ensure a fair test in an excellent experiment. As the independent variable is being changed by an experimenter or scientist, data is being recorded simultaneously as they are collected.

3 0
1 year ago
Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
REY [17]

Answer:

34.7mL

Explanation:

First we have to convert our grams of Zinc to moles of zinc so we can relate that number to our chemical equation.

So: 6.25g Zn x (1 mol / 65.39 g) = 0.0956 mol Zn

All that was done above was multiplying the grams of zinc by the reciprocal of zincs molar mass so our units would cancel and leave us with moles of zinc.

So now we need to go to HCl!

To do that we multiply by the molar coefficients in the chemical equation:

\frac{0.0956g Zn}{1 } (\frac{2 mol HCl}{1molZn})

This leaves us with 2(0.0956) = 0.1912 mol HCl

Now we use the relationship M= moles / volume , to calculate our volume

Rearranging we get that V = moles / M

Now we plug in: V = 0.1912 mol HCl / 5.50 M HCl

V= 0.0347 L

To change this to milliliters we multiply by 1000 so:

34.7 mL

7 0
3 years ago
What do we call compounds that will not dissolve in water
denis-greek [22]

Answer:

covalent compounds

Explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the purpose of sodium and chloride ions in the exoeruent?
    14·1 answer
  • The standard lab thermometer in a high school science lab contains
    12·2 answers
  • What is the mass of bismuth carbonate (597.99 g/mol) that decomposes to release 50.0ml of carbon dioxide gas at stp? 0.000445 g
    11·1 answer
  • Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of Iron(III) oxide yielded
    10·1 answer
  • If the pressure of a gas is 100 kPa when the volume is measured to be 500 mL. What pressure would need to be exerted to have the
    12·1 answer
  • Why do scientists measure and record the mass of objects rather than their weight?
    9·1 answer
  • A student was given four unknown solutions. Each solution was checked for. conductivity and tested with. phenolphthalein. The re
    15·1 answer
  • (R)-Limonene is found in many citrus fruits, including oranges and lemons. Draw its structures and identify the relationship bet
    11·1 answer
  • What is the part of the male reproductive organ that stores newly-formed sperm cell?
    5·1 answer
  • Example: Sugar (C12H22O11) - Add up the masses of each element. (Look at your periodic table for the masses.)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!