A student added 3 gms one substance in a beaker and then added 4 gms of another substance. A chemical reaction took place in the
1 answer:
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Answer:
Explanation:
Step 1. Calculate the pOH
pOH =-log[OH⁻]
pOH =-log(1.0 × 10⁻⁹)
pOH = 9.00
Step 2. Calculate the pH
pH + pOH = 14.00
pH + 9.00 = 14.00
Answer:
9000J
Explanation:
Given parameters:
Mass of the jet fighter = 5kg
Velocity = 60m/s
Unknown:
Kinetic energy of the jet fighter = ?
Solution:
The kinetic energy of a body is the energy due to motion of the body.
It is mathematically expressed as;
K.E = m v²
m is the mass
v is the velocity
So;
K.E = x 5 x 60² = 9000J
Answer: The time for activity to fell from 800 counts per second to 200 counts per second is 20 minutes
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for finding the rate constant:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
b) for activity to fell from 800 counts per second to 200 counts per second.
The time for activity to fell from 800 counts per second to 200 counts per second is 20 minutes