a light wave travels from air into a medium of refractive index 1.54. If the wavelength of the light in air is 5.4 * 10^-7. calc
1 answer:
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Answer:
Explanation:
We know that when we don't have air friction on a free fall the mechanical energy (I will symbololize it with ME) is equal everywhere. So we have:
where me(1) is mechanical energy while on h=10m
and me(2) is mechanical energy while on the ground
Ek(1) + DynamicE(1) = Ek(2) + DynamicE(2)
Ek(1) is equal to zero since an object that has reached its max height has a speed equal to zero.
DynamicE(2) is equal to zero since it's touching the ground
Using that info we have
we divide both sides of the equation with mass to make the math easier.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
Explanation:
From the question we are told that
The image distance is
The value of the image is negative because it is on the same side with the corrective glasses
The object distance is
The reason object distance is because the object father than it being picture by the eye
General focal length is mathematically represented as
substituting values
=>
Generally the power of the corrective lens is mathematically represented as
substituting values
