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adoni [48]
3 years ago
10

How many grams of carbon dioxide (CO2) are produced from the combustion of 13.00 g of CH4?

Chemistry
1 answer:
boyakko [2]3 years ago
6 0

Answer:

35.68g CO2

Explanation:

we use the combustion equation with CH4:

CH4+ O2= CO2 + H2O

And then balance it:

CH4+ 2O2= CO2 + 2H2O

Using this equation we can use sociometry:

13g CH4*\frac{1molCH4}{16.032gCH4} *\frac{1mol CO2}{1molCH4} *\frac{44g CO2}{1mol CO2}=35.68g CO2

We know that  16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.

The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.  

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How much more acidic is a person’s blood if it has a pH of 7.3 compared to its preferred 7.4? How much more alkaline is a person
enot [183]

Answer:

0.1 and 0.2.

Explanation:

The person's blood is 0.1 decreases and become more acidic if it has a pH of 7.3 compared to its preferred 7.4 while on the other hand, the person's blood is 0.2 increases and become more alkaline it has a pH of 7.6rather than its preferred 7.4. There is 0.1 decrease and 0.2 increase in the pH of the person's blood. If the pH decreases so it means it moves towards more acidic whereas, if the pH increases there is moves towards alkaline.

4 0
3 years ago
1
larisa [96]

Answer:

group I: alkali metals

group II (beryllium to radium): alkaline earth metals

group II (scandium to zinc , yttrium to cadmium, lanthanoid series to mercury, actinoid series to copernicium): transition metals

group VII (fluorine to astatine): halogens

group VIII: (helium to radon): noble gases

Explanation:

3 0
3 years ago
The part of the flower responsible for producing pollen (sperm) is the _______.
IgorC [24]
Hello,

Here is your answer:

The proper answer to this question is option C "stigma".

Here is how:

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Your answer is C.

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Hope this helps!
7 0
3 years ago
A student performs the reduction of 4-nitrobenzaldehyde (151.12 g/mol) with sodium borohydride (37.83 g/mol) in the presence of
Leviafan [203]

Answer:

65.4%

Explanation:

The redox reaction is a 1:1:1 reaction because the reagents suffer a double displacement reaction, and the substance that is substituted have the same charge (H+ and Br-), thus, we first need to know which of the reagents is the limiting.

Let's test the 4-nitrobenzaldehyde as the limiting. The mass needed for sodium borohydride (m) is the mass given of 4-nitrobenzaldehyde multiplied by the stoichiometric mass of sodium borohydride divided by the stoichiometric mass of 4-nitrobenzaldehyde. The stoichiometric mass is the number of moles in the stoichiometric representation (1:1:1) multiplied by the molar mass, so:

m = (4.13 * 37.83*1)/(151.12*1)

m = 1.034 g

So, the mass needed of the other reagent is larger than the mass that was given, so, it will be the limiting, and the stoichiometric calculus must be done with it.

The mass of the product that was expected is then:

m = (0.700*153.14*1)/(37.83*1)

m = 2.83 g

The percent yield is the mass that was formed divided by the expected mass, and then multiplied by 100%:

%yield = (1.85/2.83)*100%

%yield = 65.4%

8 0
3 years ago
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