When an electron<span> is hit by a photon of light, it absorbs the quanta of </span>energy<span> the photon was carrying and moves to a higher </span>energy<span> state. One way of thinking about this higher </span>energy<span> state is to imagine that the </span>electron<span> is now moving faster, (it has just been "hit" by a rapidly moving photon).</span>
Answer:
The average speed of the cyclist is 17.14 km/hr
Explanation:
Given;
total distance traveled by the cyclist's, d = 60 km
time taken by the cyclist, t = 3.5 hours
The average speed of the cyclist is given by;
average speed = total distance traveled / total time taken
average speed = 60 km / 3.5 hr
average speed = 17.14 km/hr
Therefore, the average speed of the cyclist is 17.14 km/hr
I choose the option D.
The velocity is constant, so it’s acceleration is 0 m/s^2.
X = 2 + 15 x 1 + 0 = 17 m
Answer:
5m
Explanation:
Using Pythagoras theorem,
a^2+ b^2=c^2
3^2+4^2=c^2
25=c^2
√(25)=c
5m=c
Answer:
v = 719.2 m / s and a = 83.33 m / s²
Explanation:
This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is
v - v₀ =
ln (M₀ / M)
where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket
In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s
m_fuel = 75 10
m_fuel = 750 kg
As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is
M = 3000 -750 = 2250 kg
let's calculate
v - 0 = 2500 ln (3000/2250)
v = 719.2 m / s
To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is
Push = v_{e} dM / dt
let's calculate
Push = 2500 75
Push = 187500 N
If we use Newton's second law
F = m a
a = F / m
let's calculate
a = 187500/2250
a = 83.33 m / s²