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alexira [117]
3 years ago
14

An old wheat-grinding wheel in a museum actually works. The sign on the wall says that the wheel has a rotational acceleration o

f 220 rad/s2 as its spinning rotational speed increases from zero to 1600 rpm.How long does it take the wheel to attain this rotational speed?
Physics
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

0.76 s

Explanation:

We use the formula for rotational speed, ω given its rotational acceleration α . ω = ω₀ + α(t - t₀) where ω₀ = initial rotational speed, ω = final rotational speed, ω₀ = initial rotational speed, α = rotational acceleration and t = initial time and t₀ = final time.

Since the wheel starts from rest, ω₀ = 0 and t₀ = 0. Given that α = 220 rad/s² and ω = 1600 rpm = 1600 × 2π/60 rad/s = 167.55 rad/s. Substituting these values into the equation ω = ω₀ + α(t - t₀)

167.55 = 0 + 220(t - 0) = 220t

So, t = 167.55/220 = 0.762 s ≅ 0.76 s

So, it takes the wheel 0.76 s to attain this rotational speed

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There is no soil in a hole

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Andy is entering early adolescence. although he used to be a big help to his mother by doing household chores, he now refuses, s
o-na [289]

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a. gender intensification

Explanation:

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8 0
3 years ago
Joe balances a stationary coin on the the tip of his finger 20 cm from the top of the table. How much work is Joe doing?
adell [148]

The work done by Joe is 0 J.

<u>Explanation</u>:

When a force is applied to an object, there will be a movement because of the applied force to a certain distance. This transfer of energy when a force is applied to an object that tends to move the object is known as work done.

The energy is transferred from one state to another and the stored energy is equal to the work done.

                                 W = F . D

where F represents the force in newton,  

          D represents the distance or displacement of an object.

Force = 0 N,   D = 20 cm = 0.20 m

                                 W = 0 \times 0.20 = 0 J.

Hence the work done by Joe is 0 J.

7 0
3 years ago
The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.
andrey2020 [161]
<span>The speed of longitudinal waves, S, in a thin rod = âšYoung modulus / density , where Y is in N/m^2. So, S = âšYoung modulus/ density. Squaring both sides, we have, S^2 = Young Modulus/ density. So, Young Modulus = S^2 * density; where S is the speed of the longitudinal wave. Then Substiting into the eqn we have (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 *10^6 = 26.01 * 2.7 * 10^ (6+3) = 70.227 * 10 ^9</span>
5 0
3 years ago
A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
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