<span>Triangles exist:
</span>3 acute angles<span>
2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>
Answer:
it does have a solution x=0
Step-by-step explanation:
9x+15=3x+15
6x+15=15
6x=0
x=0
Answer:
2 and 3
Step-by-step explanation:
To simplify this expression, you will need to use the distributive property.
Multiply -2/5 by 15 = <u>- 6</u>, -2/5 by -20d = <u>8d</u>, and -2/5 by 5c = <u>-2c</u>.
you can switch these around to get -6 + 8d - 2c and -2c + 8d - 6.
Hope this helps :)
