There are 1.50 x10^6 atoms of nitrogen in 10 grams of NH4NO3. You convert the grams to moles first and then using the definition of a mole you determine the number of molecules.
Answer:
Na F
Explanation:
because electrovalent bond is present between them
Answer:
M = 2.26 M
Explanation:
In this case, we can use an expression real short and easy to understand to calculate the molarity of any solution if we know the density, %.
M = d * % * 1000 / 100 * MM (1)
The number 1000, comes from the fact that we are assuming that we have 1 liter of solution (or 1000 mL) and the 100 comes from the purity of the compound which it can be 100%.
Now with the given data, all you have to do is to replace the given data in the above expression to get the molarity:
M = 1.09 * 17 * 1000 / 100 * 82
<em><u>M = 2.26 M</u></em>
Answer:
The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. ... If we account for all reactants and products in a chemical reaction, the total mass will be the same at any point in time in any closed system.
<u>Answer:</u> The net ionic equation is written below.
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:
![Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)](https://tex.z-dn.net/?f=Na_2CO_3%28aq.%29%2BNiCl_2%28aq.%29%5Crightarrow%202NaCl%28aq.%29%2BNiCO_3%28s%29)
Ionic form of the above equation follows:
![2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)](https://tex.z-dn.net/?f=2Na%5E%7B%2B%7D%28aq.%29%2BCO_3%5E%7B2-%7D%28aq.%29%2BNi%5E%7B2%2B%7D%28aq.%29%2B2Cl%5E%7B-%7D%28aq.%29%5Crightarrow%20NiCO_3%28s%29%2B2Na%5E%2B%28aq.%29%2B2Cl%5E-%28aq.%29)
As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
![Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)](https://tex.z-dn.net/?f=Ni%5E%7B2%2B%7D%28aq.%29%2BCO_3%5E%7B2-%7D%28aq.%29%5Crightarrow%20NiCO_3%28s%29)
Hence, the net ionic equation is written above.