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prisoha [69]
3 years ago
14

A graph with horizontal axis time (seconds) and vertical axis position (meters). An orange line runs straight upward from 0 seco

nd zero meters. A concave blue line runs upward from the same point. Maia says that both lines on this position vs time graph show acceleration. Is she correct? Why or why not?
Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

Maia is not correct because a straight line moving upwards on a position vs time graph has a constant slope, so it represents constant velocity. No change in velocity means no acceleration is taking place. Is the correct answer! :)

Explanation:

The Person/ People in the comments is correct!

OLga [1]3 years ago
6 0

Answer:

Let's start by using the definition of acceleration. Acceleration is defined as the change in velocity over the change in time. In equation, that would be Δvelocity/Δtime. Based on the axes of the given graph, it shows the trend of position over time. So, the slope of the line and the curve shows the change of position over change of time, Δdistance/Δtime. In physics, this is the definition of speed or velocity. So, Maia is incorrect. Both curves show the speed or velocity of the object, and not acceleration.  If the graph used a y-axis of velocity instead of position, then only at that instance, would be Maia be correct.

The difference between the two is, the straight line shows constant velocity while the curve line shows changing velocity.

Explanation:

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What amount of sucrose (C12H22O11) should be added to 5.83 mol water to lower the vapor pressure of water at 50 °C to 72.0 torr?
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Answer:

The amount of sucrose that must be added is 1.66 moles

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Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

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Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

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1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

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