The ability for a substance to rust is

Consider the reaction of solid aluminum iodide and potassium metal to form solid potassium iodide and aluminum metal.The balance

ratelena [41]

Answer:

674.26 g of AlI₃

Explanation:

We'll begin by calculating the theoretical yield of aluminum (Al). This can be obtained as follow:

Percentage yield of Al = 67.8%

Actual yield of Al = 30.25 g

Theoretical yield of Al =?

Percentage yield = Actual yield /Theoretical yield × 100/

67.8% = 30.25 / Theoretical yield

67.8 / 100 = 30.25 / Theoretical yield

0.678 = 30.25 / Theoretical yield

Cross multiply

0.678 × Theoretical yield = 30.25

Divide both side by 0.678

Theoretical yield = 30.25 / 0.678

Theoretical yield of Al = 44.62 g

Next, we shall determine the mass of AlI₃ that reacted and the mass of Al produced from the balanced equation. This can be obtained as follow:

AlI₃(s) + 3K(s) → 3KI(s) + Al(s)

Molar mass of AlI₃ = 27 + (3×127)

= 27 + 381 = 408 g/mol

Mass of AlI₃ from the balanced equation = 1 × 408 = 408 g

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 1 × 27 = 27 g

Summary:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Finally, we shall determine the mass of

AlI₃ required to produce 44.62 g of Al. This can be obtained as follow:

From the balanced equation above,

408 g of AlI₃ reacted to produce 27 g of Al.

Therefore, Xg of AlI₃ will react to produce 44.62 g of Al i.e

Xg of AlI₃ = (408 × 44.62)/27

Xg of AlI₃ = 674.26 g

Thus, 674.26 g of AlI₃ is needed for the reaction.

8 0

4 years ago

What is the main problem associated with metal refining?

yanalaym [24]

Answer:

It is extremely dangerous. It does not provide very much refined Metal. It generates a great deal of waste.

Explanation: Very harmful.

7 0

3 years ago

How do two elements change properties when they form a compound

S_A_V [24]

In most cases, when two elements form a compound, the new compound has a set of chemical properties that are entirely different from its reactants. However, in the case of diatomic compounds, such as O2, then yes, the compound retains the properties of its elemental parts.

5 0

3 years ago

0.158 g of a mystery molecule is placed into a bomb calorimeter that has a heat capacity of 1650 J/C. After the sample is combus

Lunna [17]

Answer: The molar mass of the mystery element is 111.27 g/mol

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

$q=c\Delta T$

where,

q = heat absorbed

c = heat capacity of calorimeter = 1650 J/°C

$\Delta T$ = change in temperature = $2.54^oC$

Putting values in above equation, we get:

$q=1650J/^oC\times 2.54^oC=4191kJ$

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles of the mystery molecule, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = -4191 J

n = number of moles = ? moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -2960 kJ/mol = -2960000 J/mol (Conversion factor = 1 kJ = 1000 J)

Putting values in above equation, we get:

$-2960000=\frac{-4191J}{n}\\\\n=\frac{-4191}{-2960000}=0.00142mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of mystery molecule = 0.158 g

Moles of mystery molecule = 0.00142 mol

Putting values in above equation, we get:

$0.00142mol=\frac{0.158g}{\text{Molar mass of mystery molecule}}\\\\\text{Molar mass of mystery molecule}=\frac{0.158}{0.00142}=111.27g/mol$

Hence, the molar mass of the mystery element is 111.27 g/mol

8 0

3 years ago

When using the process of evaporation to separate a mixture, what is left behind

brilliants [131]

Answer:

When a solution is heated, the solvent evaporates, leaving behind the dissolved solids as residue. When a solution containing dissolved solutes is heated, the solvent will evaporate. Only the solute will remain in the evaporating dish.

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8 0

3 years ago