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umka21 [38]
3 years ago
14

Balance and classify this reaction: C6H6 +02 →CO2 +H₂O

Chemistry
1 answer:
laila [671]3 years ago
6 0
This is a combustion reaction.
2C6H6 + 9O2➡️ 6CO2 + 6H2O
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How should the ph of a 0.1 m solution of nac2h3o2 compare with that of a 0.1 m solution of kc2h3o2?
Semenov [28]

We have that for the Question it can be said that the NaOH combines with CH_3COOH to produce CH_3COONa (Salt)

From the question we are told

how should the ph of a 0.1 m solution of <em>nac2h3o2</em> compare with that of a 0.1 m <u>solution </u>of kc2h3o2?

Generally

with  the ph of a 0.1 m solution of <em>nac2h3o2</em> compared with that of a 0.1 m <u>solution </u>of kc2h3o2 ,we see that the salt produce  is a weak acid and strong akali salt

We see that the salt produced in water gives a base from the derived weak acid

The salt produce is CH_3COONa

Therefore

the NaOH combines with CH_3COOH to produce CH_3COONa (Salt)

For more information on this visit

brainly.com/question/17756498

7 0
3 years ago
What method would you use to find the volume of an irregularly shaped object?
dimulka [17.4K]
Displacement, usually the method that is used to measure the volume of an irregularly shaped object.
4 0
4 years ago
Is A car traveling 33 km/h. accelerating
MArishka [77]

Answer:

where is the question?

Explanation:

5 0
3 years ago
The planet Saturn has a mass of 5.69x10 26 and volume 8.01x10 23 m3 what is the density of Saturn ? Would Saturn sick or float i
Ad libitum [116K]

Density = mass/volume

We are given a mass (which I am assuming is in kilograms) and a volume.  Divide to find density.

Density of Saturn = 5.69x10²⁶ kg / 8.01x10²³ m³

Density of Saturn = 710. kg/m³

The density of water is 1000 kg/m³, which is higher than the density of Saturn.  Since Saturn has a lower density than water, theoretically, Saturn would float in a gigantic bathtub filled with water.

<h3>Answer:</h3>

Density: 710. kg/m³

Float? Yes.

6 0
4 years ago
Read 2 more answers
1. Identify all of the gas law equations that relate to the ideal gas law.
zheka24 [161]

Explanation:

1)  PV = nRT(ideal gas equation )

All of the gas laws equations that relate to the ideal gas law:

1. Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.  

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

2. Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

3. Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

4. Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

2)

Initial moles of gas = n_1=0.0400 mol

Initial volume of the gas = V_1=500 mL=0.5 L (1 mL = 0.001 L)

Final moles of gas = n_2=?

Final volume of the gas = V_2=1.00 L

Equation used to find the amount of gas added is Avogadro's law equation :

\frac{V_1}{n_1}=\frac{V_2}{n_2}

n_2=\frac{V_2\times n_1}{V_1}=\frac{1.00 L\times 0.0400 mol}{0.5 L}

n_2=0.08 mol

3 0
3 years ago
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