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Roman55 [17]
3 years ago
6

A student adds a rectangular block of mass 26.10 g to a graduated cylinder initially filled with 40.1 mL of water, but some wate

r
splashes out of the cylinder. As a result, the student reads the new level of the water to be 42.7 ml. Previously, the student had
measured the length, width and height of the block to be 3.0 cm by 1.0 cm by 1.0 cm.
Does the splash cause the volume of the block to be reported as too high or too low, compared to the volume calculated from the
length measurements?
Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

The splash cause the volume of the block to be too high

Explanation:

This is because, from the previous measurement made by the student, the volume of the block is 5.7ml higher.

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Zn+2HCl=ZnCl2+H2 How many grams of ZnCl2 will be produced from 26.0 g of Zn and 42.0 g of HCl?
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53.14 grams of ZnCl_{2}  will be produced from 26.0 g of Zn and 42.0 g of HCl.

Explanation:

Balanced chemical reaction:

Zn + 2 HCl ⇒ ZnCl_{2} +  H_{2}

data given:

mass of Zn = 26 grams

mass of HCl = 42 grams

mass of ZnCl_{2} = ?

here in the reaction Zn is the limiting reagent so mass of

ZnCl_{2} formed will be determined by it.

atomic mass of zinc =65.38 grams/mole

number of moles = \frac{mass}{atomic mass of 1 mole}

putting the values in the above equation:

number of moles of zinc = \frac{26}{65.38}

number of moles of zinc = 0.39 moles

From the balanced reaction it is seen that

1 mole of Zn produced 1 mole of ZnCl_{2}

0.39 moles will produce x moles of ZnCl_{2}

0.39 moles of ZnCl_{2} (atomic mass of  Zn = 65.38 grams/mole)

mass = atomic mass x number of moles

         = 0.39 x 136.28

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How many moles of ammonia could be obtained from a maximum of 5.0 moles of nitrogen​
Orlov [11]

Answer:

10 moles of ammonia could be obtained from a maximum of 5.0 moles of nitrogen​.

Explanation:

The balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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Then you can apply the following rule of three: if by reaction stoichiometry 1 mole of nitrogen produces 2 moles of ammonia, 5 moles of nitrogen produces how many moles of ammonia?

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moles of ammonia= 10

<u><em>10 moles of ammonia could be obtained from a maximum of 5.0 moles of nitrogen​.</em></u>

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