Station model, a pattern of meteorological symbols that represents the wheater at a particular observing station
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
No why are you asking this question?
Answer:
8.1g
0.1g
Explanation:
The reaction expression is given as:
Fe + 2HBr → FeBr₂ + H₂
Mass of pure iron given = 2.8g
A. Mass of HBr needed to dissolve a padlock of the mass;
To solve this problem, we need to use the mole concept.
Convert mass of the known iron to the number of moles.
Number of moles =
Molar mass = 56g/mol
Number of moles of iron =
= 0.05mole
1 mole of Fe will react with 2 mole of HBr
0.05mole of Fe will react with 0.05 x 2 = 0.1mole of HBr
Mass of HBr = number of moles x molar mass
Molar mass of HBr = 1 + 80 = 81g/mol
Mass of HBr = 0.1 x 81 = 8.1g
B. What mass of H2 would be produced by the complete reaction of the iron bar
Since:
1 mole of Fe will produce 2 mole of hydrogen gas
0.05mole of Fe will produce 2 x 0.05mole = 0.1mole of hydrogen gas
Mass of hydrogen gas = number of moles x molar mass
= 0.1 x 1
= 0.1g