Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
the last option
Step-by-step explanation:
can you show the rest of the last option? if there isn't anything cutoff, then the last option would be correct. also, you can use desmos .com next time to help you graph
the answer is c and I think it's 300