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Inessa05 [86]
3 years ago
10

Which of the following must be the same before and after a chemical reaction?

Physics
1 answer:
madam [21]3 years ago
6 0

Answer: Option (D) is the correct answer.

Explanation:

A chemical reaction is defined as the reaction which causes change in chemical composition of a substance.

According to law of conservation of mass, mass can neither be created nor it can be destroyed. It can only be changed from one form to another.

For example, H^{+} + Cl^{-} \rightarrow HCl

Here, total mass of reactants = (1.008 + 35.453) g/mol = 36.461 g/mol

Whereas total mass of products = 36.461 g/mol

This shows that mass remains the same before or after the reaction.

Similarly, the number of atoms of the type involved will remains the same as no change in their nucleus is occurring.

Thus, we can conclude that the following must be the same before and after a chemical reaction.

  • The sum of the masses of all substances involved.
  • The number of atoms of the type involved.
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The water hose at your home outputs 24 gallons of water a minute. how many cubic centimeters per second does the hose output? th
adoni [48]

When we convert 24 gallon/min to cubic centimeters per second (cm³/s), the result obtained is 1514.164 cm³/s

<h3>How to convert 24 gallon/min to cm³/min</h3>

We'll begin by converting 24 gallon/min to cm³/min. This can be obtained as follow:

1 gallon/min = 3785.41 cm³/min

Therefore,

24 gallon/min = (24 gallon/min × 3785.41 cm³/min) / 1 gallon/min

24 gallon/min = 90849.84 cm³/min

<h3>How to convert 90849.84 cm³/min to cm³/s</h3>

We can convert 90849.84 cm³/min to cm³/s as follow:

60 cm³/min = 1 cm³/s

Therefore,

90849.84 cm³/min = (90849.84 cm³/min × 1 cm³/s) / 60 cm³/min

90849.84 cm³/min = 1514.164 cm³/s

Thus,

24 gallon/min = 1514.164 cm³/s

Learn more about conversion:

brainly.com/question/2139943

#SPJ1

7 0
1 year ago
Someone please help me! Please help
Andrei [34K]

Answer:

Explanation:

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5 0
2 years ago
I NEED HELP :) ty.............
Black_prince [1.1K]

Answer:

The answer to your question is given below

Explanation:

From the question given above, we can see that the wave with a higher frequency has a shorter wavelength while that with a lower frequency has a longer wavelength. This is so because the frequency and wavelength of a wave has inverse relationship. This can further be explained by using the following formula:

Velocity = wavelength x frequency

Divide both side by wavelength

Frequency = Velocity /wavelength

Keeping the velocity constant, we have:

Frequency ∝ 1 / wavelength

From the above illustration, we can see clearly that the frequency and wavelength are in inverse relationship. This implies that the higher the frequency, the shorter the wavelength and the shorter the frequency, the higher the wavelength.

7 0
2 years ago
A very thin oil film (n = 1.25) floats on water (n = 1.33). What is the thinnest film that produces a strong reflection for gree
mixer [17]

Answer:

200 nm is the thinnest film that produces a strong reflection for green light with a wavelength of 500 nm

Explanation:

If two reflected waves interfere constructively ,strong reflection is produced. Two reflected waves will experience a phase change

For constructive interference

2\times n\times t=m\lambda

for thinnest film m=1

refractive index should be taken for film n=1.25

thickness of the thinnest film is

t=\frac{m\lambda}{2n} \\t=\frac{1\times 500}{2\times 1.25} \\t=200 nm

6 0
3 years ago
Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. A
Crazy boy [7]

Answer:

W = 1884J

Explanation:

This question is incomplete. The original question was:

<em>Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction. </em>

<em> How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.</em>

The amount of work done by the motor is given by:

W=\Delta K

W= 1/2*I*\omega f^2-1/2*I*\omega o^2

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

\omega f^2=\omega o^2+2*\alpha*\theta

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

\tau=I*\alpha

\alpha=\tau/I     =>     \alpha = 0.5rad/s^2

Now we can calculate the final velocity:

\omega f = 8.68rad/s

Finally, we calculate the total work:

W= 1/2*I*\omega f^2 = 1883.56J

Since the question asked to "<em>Enter your answer in joules to four significant figures.</em>":

W = 1884J

3 0
3 years ago
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