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TiliK225 [7]
3 years ago
14

Express 8% as a decimal

Mathematics
2 answers:
konstantin123 [22]3 years ago
5 0

Answer:

0.08

Step-by-step explanation:

Papessa [141]3 years ago
3 0

Answer:

you move the decimal to the right twice so i think its 0.08

Step-by-step explanation:

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fiona is going to jog once around the block she lives on. The block is retangular, and it is 180 yards long and 200 feet wide. H
prisoha [69]

Answer:

1480 feet

Step-by-step explanation:

180yd x 2 = 360yd

change to feet: 360 x 3 = 1080 feet

200ft x 2 = 400ft

1080 + 400 = 1480ft

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3 years ago
Find the measure of each interior angle of the regular polygon
jek_recluse [69]
I believe 60 degree is your answer
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What is the volume of the following cylinder in cubic feet?
Salsk061 [2.6K]
5089.38 is the volume
5 0
2 years ago
Please help and show work
mylen [45]
7.B
\sqrt{\pi } = 1.772
\pi = 3.142
2 \times \pi = 6.283
{\pi}^{2} = 9.869

9.A
3/2=1.5

8. F
2times pi =6.283
square root of 50= 7.071
pi squared/2= 3.289

10.H
1/7= .143
which means it can't be f or g.

8 0
3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
2 years ago
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