13) A mass attached to the free end of a spring executes simple harmonic motion according to the equation y = (0.50 m) sin (18π
1 answer:
Hi there!
The period is given by:
T = Period (sec)
w = angular frequency (rad/sec)
According to the equation for SHM in terms of position:
y(t) = Asin(ωt + φ)
A = Amplitude (m)
ω = angular frequency (rad/sec)
t = time (sec)
φ = phase angle
In this instance, the angular frequency is given as 18π.
Plug this value into the equation for T:
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Answer:
the magnitude of the magnetic field is 8.704 x 10⁻⁴ T
Explanation:
Given;
potential difference, V = 278 V
radius of the circular path, r = 6.46 cm = 0.0646 m
charge of electron, q = 1.60218 × 10⁻¹⁹ C
mass of electron, m = 9.10939 × 10⁻³¹ kg
The magnitude of the magnetic field is given as;
where;
B is the magnitude of the magnetic field
is mass of the electron
v is velocity of the electron
r is the radius of the circular path
q is charge of the electron
Determine velocity of the electron from kinetic energy equation;
the magnitude of the magnetic field:
Therefore, the magnitude of the magnetic field is 8.704 x 10⁻⁴ T