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yulyashka [42]
2 years ago
9

En 200 gramos de carburo de potasio ,cuya fórmula química es K4C , Cuántos moles de esa sustancia existen ?

Chemistry
1 answer:
WARRIOR [948]2 years ago
3 0

Answer:

i would happily help but i don't understand that language sorry

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1s^{2}  2s^{2}  2p^{6}  3s^{2}
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3 years ago
(a) How much negative charge is on each oxygen of the carbonate ion?
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The chemical formula of a carbonate ion is CO3^2-. It is an AX3 system which means it take the trigonal planar shape. There would be two single bonds of C-O and one double bond C-O in order for C to agree with the octet rule. Two minus charges are equally distributed to the three oxygen atoms so that each oxygen of the carbonate ion would have a charge of negative 2/3.
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3 years ago
How many ml of a 2.0 m nabr solution are needed to make 200.0 ml of 0.50 m nabr?
gogolik [260]

To solve this we use the equation,

 

<span> M1V1 = M2V2</span>

 

<span> where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.</span>

 

<span>2.0 M x V1 = 0.50 M x 200 mL</span>

<span>V1 = 50 mL needed</span>

4 0
3 years ago
At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?
rjkz [21]
E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
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b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
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8 0
3 years ago
2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
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