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krek1111 [17]
3 years ago
9

certain conductor with a resistance of 10 Ohms is crossed by an electric current of intensity 100 mA. What is the potential diff

erence at the terminals of that conductor?
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

1.0 V

Explanation:

Step 1: Given data

  • Resistance of certain conductor (R): 10 Ω
  • Current's intensity (I): 100 mA
  • Potential difference at the terminals of that conductor (V): ?

Step 2: Convert "I" to Ampere

We will use the conversion factor 1 A = 1000 mA.

100 mA × 1 A/1000 mA = 0.100 A

Step 3: Calculate the potential difference

We will use Ohm's law.

V = I × R

V = 0.100 A × 10 Ω = 1.0 V

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15. What volume of CCI, (d = 1.6 g/cc) contain
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Answer:

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Explanation:

1. Moles of CCl₄

n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}

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4. Volume of CCl₄

V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}

4 0
3 years ago
Stan skephalo???????????
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Answer:

,`.-`;'

Explanation:

c

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3 years ago
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QUICK HELP PLEASE!!?? Need answer QUICK
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Answer:

B

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Now, look for the solubility curve of Na_2HAsO_4; it's the yellow-orange line. Find out what the y-coordinate of the point where x = 60 is on the line: it's around (60, 65).

So, since the point (60, 60) is below the line corresponding to this substance, Na_2HAsO_4 is unsaturated.

The answer is B.

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4 years ago
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Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
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<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
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</span>
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In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

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Then, the equation to relate ΔG° to the equilibrium constant K is

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