Answer:
The percentage ductility is 35.5%.
Explanation:
Ductility is the ability of being deform under applied load. Ductility can measure by percentage elongation and percentage reduction in area. Here, percentage reduction in area method is taken to measure the ductility.
Step1
Given:
Diameter of shaft is 10.2 mm.
Final area of the shaft is 52.7 mm².
Calculation:
Step2
Initial area is calculated as follows:
A = 81.713 mm².
Step3
Percentage ductility is calculated as follows:
D = 35.5%.
Thus, the percentage ductility is 35.5%.
Answer:
Machine 2 has a higher process capability index, it would be best considered for purchase.
Explanation:
Process capability index: Cpk= Min [(mean-L spec)/3sd; (U spec-mean)/3sd]
For machine 1, mean= 48mm and L spec= 46 and U spec= 50, Standard deviation sd= 0.7
Cpk= [0.952;0.952]= 0.952
For machine 2, mean= 47 and L spec= 46 and U spec= 50, Standard deviation sd= 0.3
Cpk= [1.111;3.333]= 1.111
It is clearly observed from the calculations above that the Cpk value of machine 2 is higher than that of machine 1.
Since machine 2 has a higher process capability index, it would be best considered for purchase.
The true statement about the dot plot is 1 has 4 and 0 dots.
Explanation:
- after creating a Bar chart 4 is the right answer.
- The highest among st all the other plots is 1 but 4 shows 3.
- Taking an average from all the data points 3 comes to the right answer.
- Median the central Mid-point is 3.
- Mode also comes to 3.
- It is skewed on the right due to the 1st one.
- Skewed shows the data point either increasing or in decreasing.
- There a to Bi- histograms which has two ups and downs.
- The true statement has to be as Mean=Median=Mode is 3.
Answer:
See explaination
Explanation:
See attachment for the detailed step by step solution of the given problem.
