Question

Suppose the loop is moving toward the solenoid (to the right). Will current flow through the loop down the front, up the front, or not at all? Explain in terms of magnetic forces exerted on the charges in the wire of the loop. Describe the direction of the magnetic moment of the loop. Given your answer, do you expect the loop to be attracted toward or repelled from the solenoid?

Answer 1

Answer:

See explanation

Explanation:

The magnetic force is

F = qvB sin θ

We see that sin θ = 1, since the angle between the velocity and the direction of the field is 90º. Entering the other given quantities yields

F

=

(

20

×

10

−

9

C

)

(

10

m/s

)

(

5

×

10

−

5

T

)

=

1

×

10

−

11

(

C

⋅

m/s

)

(

N

C

⋅

m/s

)

=

1

×

10

−

11

N

Answer 2

Answer:

If the loop is moving toward the solenoid (to the right). The current flow through the loop up the front(From the right hand rule).

The magnetic force acting on the charges in the wire of the loop, will induce a current in the opposite direction to change producing it(This is Lenz law). This magnetic force on the charges will set up a magnetic moment in the opposing direction to the loop direction.

It is expected the the loop will be repelled from the solenoid.

Explanation:

Magnetic moment is set on the charges in a loop, under an influence of magnetic force. The directions of these quantities can be observed using the Right-Hand Rule and Lenz's law.

Directions of currents and associated magnetic fields can all be found using only the Right Hand Rule. When the fingers of the right hand are pointed in the direction of the magnetic field, the thumb points in the direction of the current. When the thumb is pointed in the direction of the magnetic field, the fingers point in the direction of the current.

By applying the Lenz's law, it can be seen that the direction of the current will be such as to oppose the change.