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Stels [109]
3 years ago
12

Draw the free-body diagram of the beam which supports the 80-kg load and is supported by the

Engineering
1 answer:
Sauron [17]3 years ago
5 0

The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.

The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.

The free-body diagram is a graphical representation used to visualize the forces applied to an object.

The equilibrium of forces on the x-axis is:

\mathbf{\sum F_x  = 0}

The equilibrium of forces on the y-axis is:

\mathbf{\sum F_y = 0}

The equilibrium condition at any point is:

\mathbf{\sum M = 0}

From the free body diagram attached in the second image below,

  • the horizontal reaction is located at point A as \mathbf{ A_x}
  • the vertical reaction is  located at point A  as \mathbf{A_y}
  • the tension =  T
  • the weight = W

Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

Learn more about the free-body diagram here:

brainly.com/question/19345060?referrer=searchResults

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Statement 1: All balls hit the ground at the same time. Statement 2: All balls hit the ground with the same force. Statement 3:
laiz [17]

Answer:

Statement 1: All balls hit the ground at the same time

Explanation:

When there is no resistance of air, the acceleration due to gravity experienced by all the bodies are same. So for falling bodies, neglecting the air resistance, the falling object will be weightless and therefore all the objects will hit the ground at the same time when there is nor air resistance and the objects are considered to be falling in vacuum.

7 0
3 years ago
Question #7
Gre4nikov [31]

Answer:

The option that identifies why the bicycle cannot yet be created as a model in the scenario is;

Suzanne forgot to include the exact units of measurement that should be used

Explanation:

The design sketch turned over to the team that will work on the prototype by Suzanne should present all aspects of the design that will enable others working on the design and that make use of the sketch to have a clear understanding of what is required of them

Given that Suzanne has included the numbers that explain the relationship between the sketch and the real world object, the scale that shows the ratios and proportions of the sketch and the actual bicycle has been provided, however, given that the the machinist still need more information, the units of the measurement indicated in the drawing was not included, therefore, the actual dimensions and size that gives the length of the parts of the sketch and of the prototype to be made cannot be determined.

4 0
3 years ago
An insulated 40 ft3 rigid tank contains air at 50 lbf/in2 and 120oF. A valve connected to the tank is now opened, and air is all
goldfiish [28.3K]

Answer:

The electrical work for the process is 256.54 Btu.

Explanation:

From the ideal gas equation:

n = PV/RT

n is the number of moles of air in the tank

P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2

V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3

T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K

R is gas constant = 8.314 J/mol.k

n = 344736.2×1.133/8.314×321.9 = 145.94 mol

The thermodynamic process is an isothermal process because the temperature is kept constant.

W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu

5 0
3 years ago
Read 2 more answers
What are the mechanisms of energy transfer in an open system?
gulaghasi [49]

Answer:

mechanism of energy transfer in system is depend on Heat and Work:

Explanation:

Heat :Heat is described as the type of energy transmitted by a temperature difference between two structures (or a system and its environment).

Work:it is  is an interaction of energy between a system and its environment. In the form of  work   it can cross the boundaries of a closed system. if energy crossing boundary of the system is not heat then it must be work..

5 0
4 years ago
Would be much appreciated if someone could help with this will give brainiest.
Mashcka [7]

Answer:   both mm and inches on each dimension in a sketch (with the main dimension in one format and the other in brackets below it), in the way you can have dual dimensions shown when detailing an idw view.

personally think it would look a mess/cluttered with even more text all over the sketch environment, but everyone's differenent.

If it's any help - you know you can enter dimensions in either format?  If you're working in mm you can still dimension a line and type "2in" and vice-versa.  Probably know this already, but no harm saying it, just in case.

You can enter the units directly in or mm and Inventor will convert to current document settings (which  you can change - maybe someone can come up with a simple toggle icon to toggle the document settings).  Tools>Document Settings>Units

Unlike SolidWorks when you edit the dimension the original entry shows in the dialog box so it makes it easy to keep track of different units even if they aren't always displayed.  (SWx does the conversion or equation and then that is what you get.)

I work quite a bit in inch and metric and combination (ex metric frame motor on inch machine) and it doesn't seem to be a real difficulty to me.

4 0
3 years ago
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