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Tanya [424]
2 years ago
5

What do fluorine, sodium, and aluminum have in common

Physics
1 answer:
Alekssandra [29.7K]2 years ago
8 0
Both are isoelectronic with Ne; i.e., their outside shells are filled with eight electrons and all have the same number of electrons (that is the isoelectronic part).
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Help ASAP thanks !!!
Ann [662]

Answer:

true

Explanation:

3 0
3 years ago
The total resistance of the circuit <br>​
ZanzabumX [31]

The total resistance of a series circuit is equal to the sum of individual resistances. Voltage applied to a series circuit is equal to the sum of the individual voltage drops. The voltage drop across a resistor in a series circuit is directly proportional to the size of the resistor.

If you know the total current and the voltage across the whole circuit, you can find the total resistance using Ohm's Law: R = V / I. For example, a parallel circuit has a voltage of 9 volts and total current of 3 amps. The total resistance RT = 9 volts / 3 amps = 3 Ω

Current: The total circuit current is equal to the sum of the individual branch currents. Resistance: Individual resistances diminish to equal a smaller total resistance rather than add to make the total.

4 0
3 years ago
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Question 7
erastova [34]

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4 0
3 years ago
What is the difference between a mineral and a rock
Sedbober [7]

A mineral is a naturally occurring, inorganic solid with a definite chemical composition and a crystalline structure formed by geological processes.

A rock is an aggregate of one or more minerals. It may also contain organic remains and mineraloids apart from regular mineral formations. Since rocks vary in their mineral and chemical composition, they are classified according to the process of their formation.

5 0
3 years ago
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A 0.500-V potential difference is maintained across a 1.50-m length of tungsten wire that has a cross-sectional area of 0.800 mm
Genrish500 [490]

Answer:

5.95 A

Explanation:

From the question

R = ρL/A..................... Equation 1

Where R = resistance of the tungsten wire, ρ = Resistivity of the tungsten wire, L = length, A = cross sectional area.

Given: L = 1.5 m, A = 0.8 mm² = 0.8×10⁻⁶ m, ρ = 5.60×10⁻⁸ Ω.m

Substitute these values into equation 1

R = 1.5(5.60×10⁻⁸)/0.8×10⁻⁶

R = 0.084 Ω.

Finally, using Ohm law,

V = IR

Where V = Voltage, I = current

Make I the subject of the equation

I = V/R............... Equation 2

I = 0.5/0.084

I = 5.95 A

4 0
2 years ago
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