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3 years ago

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If speed is measured in meters per seconds (m/s) and time is measured in seconds, the SI unit of acceleration is m/s2. Imagine y

ou are riding a motorcycle that is accelerating at a rate of 6 m/s2. What is the motorcycle’s speed after three seconds of acceleration?

1 answer:

inessss [21]3 years ago

7 0

Answer:

please let me know when you find it

Explanation:

i have the same question and cant find it

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X-Rays contradict to?<br> a)beta b) alpha.<br> C) gamma

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<h3>X-Rays contradict to?</h3>

<h3>C. gamma </h3>

a type of penetrating electromagnetic radiation produced by the radioactive disintegration of atomic nuclei

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This version of Einstein’s equation is often used directly to find what value?

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A. THE ENERGY THAT IS RELEASED IN A NUCLEAR REACTION.

M =MASS

C^2= SPEED OF LIGHT SQUARED

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Use newton's laws to find an expression for the net external force acting on the car. ignore air resistance.

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Hi, thank you for posting your question here at Brainly.

Newton's second law of motion can be expressed as Fnet = ma. The next external for acting on, say for example, a moving car are the following:

*weight due to gravity (force down)
*friction force between he road and the car's tires (force opposite the car's direction)

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3 years ago

Assume that in interstellar space the distance between two electrons is about 0.8 cm. The electric force between the two electro

SIZIF [17.4K]

Answer:

F = 3.6 x 10⁻²⁴ N

Explanation:

The force of attraction or repulsion between two charges is given by the Coulomb's Law. Coulomb's Law states that:

F = kq₁q₂/r²

where,

F = Electric Force between electrons = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = Charge on electron = 1.6 x 10⁻¹⁹ C

r = distance between electrons = 0.8 cm = 0.008 m

Therefore,

F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(0.008 m)²

<u>F = 3.6 x 10⁻²⁴ N</u>

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3 years ago

Calculate the equivalent resistance for both circuits. Series circuit: 2 Ω and 4 Ω Parallel circuit: 2 Ω and 4 Ω Which circuit h

goldenfox [79]

Equivalent resistance is also known as the overall resistance.

For resistors in a series circuit, the total resistance is computed using the formula:

$R_{T} = R_{1}+ R_{2}+ R_{3}... R_{n}$

In other words, you just add up the resistance of each resistor in the series circuit. In your case you only have two resistors. You have 2Ω and 4Ω. So all you need to do is add that up.

$R_{T} = R_{1}+ R_{2}$
$R_{T} = 2 + 4=6$

The total resistance of the series circuit is 6Ω

In a parallel circuit you get the total resistance using the formula:
$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}...+\frac{1}{R_{n}}$

First you get the sum of all fractions and at the end take the reciprocal of the resulting fraction and divide. So let us take your problem into consideration where you have two resistors that have a resistance of 2Ω and 4Ω.

$\frac{1}{R_{T}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}$
$\frac{1}{R_{T}} = \frac{1}{2}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{2}{4}+\frac{1}{4}$
$\frac{1}{R_{T}} = \frac{3}{4}$

Get the reciprocal of the resulting fraction 3/4 and then divide. The reciprocal of 3/4 is 4/3.

4/3 = 1. 33Ω

So if you compare the equivalent resistance of the two circuits, the series circuit has a higher equivalent resistance.

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