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DerKrebs [107]
3 years ago
8

is it true that the slope of the line x = -4 is 0

Mathematics
1 answer:
Viktor [21]3 years ago
5 0
It is not true that is false
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Find the mean and the MAD. [Note: Type your answers as decimal numbers, rounded to the nearest tenth.] 135, 160, 145, 155, 170,
VashaNatasha [74]

Answer:

Mean = 151

MAD = 9.14

Step-by-step explanation:

Given the data:

135, 160, 145, 155, 170, 150, 142

Mean = Σx / n

Mean = 1057 / 7

Mean = 151

Mean absolute DEVIATION (MAD) : Σ(x - μ) / n

[(135-151) + (160-151) + (145-151) + (155-151) + (170-151) + (150-151) + (142-151)] / 7

Mean absolute deviation = 9.14

4 0
2 years ago
Need help please.........................
Archy [21]

Answer:

16t^{2} + 2t - 6

Step-by-step explanation:

(12t^{2}  + 5t -y) - (-4t^{2} + 3t -1)

simplify

12t^{2} + 5t -7 +4t^{2} -3t +1

combine like terms

16t^{2} + 2t - 6

8 0
2 years ago
There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per hour. At
kumpel [21]

Answer:

The required piece-wise linear function is

\left\{\begin{matrix}1.5x & 0\leq x

Step-by-step explanation:

Consider the provided information.

Let x represents the number of hours and S(x) represents the depth of snow.

There was no snow on the ground when it started falling at midnight at a constant rate of 1.5 inches per.

That means the depth of snow will be:

S(x)=1.5x\ \ \ 0\leq x< 4

At  4:00 a.m., it starting falling at a constant rate of 3 inches per hour,

From mid night to 4:00 a.m the depth of snow will be 1.5×4=6 inches.

If we want to calculate the total depth of snow from midnight to 7:00 am we need to add 6 inches in 3(x-4) where 4≤x<7

Therefore,

S(x)=3(x-4)+6\ \ \ 4\leq x

7:00 a.m. to 9:00 a.m., snow was  falling at a constant rate of 2 inches per hour.

From mid night to 7:00 a.m the depth of snow will be 3(7-4)+6=15 inches.

If we want to calculate the total depth of snow from midnight to 9:00 am we need to add 15 inches in 2(x-7) where 7≤x≤9

S(x)=2(x-7)+15\ \ \ 7\leq x\leq 9

Therefore, the required piece-wise linear function is

\left\{\begin{matrix}1.5x & 0\leq x

8 0
3 years ago
Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.
sveticcg [70]

Answer:

(a) x=\frac{5\pi }{3}

(b)  x=\frac{\pi }{8}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi

(a) We have given equation 2sinx+\sqrt{3}=0

sinx=\frac{-\sqrt{3}}{2}

x=sin^{-1}(-0.866)

x=\frac{-\pi }{3}=2\pi -\frac{\pi }{3}=\frac{5\pi }{3}

(b) tan(2x)=1

2x=tan^{-1}1

2x=\frac{\pi }{4}

x=\frac{\pi }{8}

7 0
3 years ago
Find the sum. Enter your answer in the box below as a fraction, using the slash mark (/) for the fraction bar. 7/17 + 9 /17​
scoundrel [369]
16/17 is the answer. you just add the numerators since they have common denominators!
3 0
3 years ago
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