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3 years ago

In real machines,efficiency is always

Physics

2 answers:

Monica [59]3 years ago

6 0

<span>In real machines, efficiency is always less than 1 .</span>

alukav5142 [94]3 years ago

4 0

Less than 100% Because from the moment it is built it begins to break down.

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Problem: A barbell consists of two small balls, each with mass m at the ends of a very low mass rod of length d. The barbell is

zepelin [54]

Answer:

mass of ball 1=m1

mass of ball 2=m2

velocity of ball=r1w1

velocity of ball 2=r2w2

Total angular momentum=m1*v1+m2*v2

but

v1=r1*w1

v2=r2*w2

Substitute values in above equation

Total angular momentum of the system=m1*r1*w1+m2*r2*w2

7 0

3 years ago

Is work done in this example: A student lifting a heavy backpack off of the floor.

vagabundo [1.1K]

I don't know what u mean

4 0

2 years ago

Read 2 more answers

Heights of men on a baseball team have a bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm

kaheart [24]

Answer:

95 %

99.7 %

Explanation:

$\mu$ = 166 cm = Mean

$\sigma$ = 5 cm = Standard deviation

a) 156 cm and 176 cm

$166-5\times 2=156$

$166+5\times 2=176$

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

$166-5\times 3 =151$

$166+5\times 3=181$

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

3 0

3 years ago

HURRY URGENT ASAP I WILL GIVE BRAINLIEST

Leto [7]

Answer:

Explanation:

4 0

3 years ago

A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i

mash [69]

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance $R_1=206ohm$

Power dissipated in this resistance is $P_1=1.30watt$

Power dissipated in the resistor is equal to $P=\frac{v_{rms}}^2{R}$

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that $\frac{P_1}{P_2}=\frac{R_2}{R_1}$

$\frac{1.3}{P_2}=\frac{532}{206}$

$P_2=0.503watt$

So power dissipated in resistor 532 ohm is 0.503 watt

5 0

3 years ago