<span>93.3°C
A temperature in Fahrenheit (°F) can be converted to Celsius (°C), using the formula
[°C] = ([°F] − 32) × 5⁄9. Here we have to convert a temperature of 200°F in to Celsius. Thus Subtract 32 from Fahrenheit and multiply by 5 then divide by 9 .
That is (200°F - 32) × 5/9=168 × 5/9
=840/9
=93.333333333°C
= 93.3°C</span>
Change in velocity = d(v)
d(v) = v2 - v1 where v1 = initial speed, v2 = final speed
v1 = 28.0 m/s to the right
v2 = 0.00 m/s
d(v) = (0 - 28)m/s = -28 m/s to the right
Change in time = d(t)
d(t) = t2 - t1 where t1 = initial elapsed time, t2 = final elapsed time
t1 = 0.00 s
t2 = 5.00 s
d(t) = (5.00 - 0.00)s = 5.00s
Average acceleration = d(v) / d(t)
(-28.0 m/s) / (5.00 s)
(-28.0 m)/s * 1 / (5.00 s) = -5.60 m/s² to the right
Explanation:
The aircraft is traveling north at 100 m/s.
The wind blows from the west (towards the east) at 25 m/s.
The two vectors form a right triangle. The magnitude of the resultant velocity can be found with Pythagorean theorem:
v² = vx² + vy²
v² = (25 m/s)² + (100 m/s)²
v = 103 m/s
The direction can be found with trigonometry:
θ = atan(vy / vx)
θ = atan(100 / 25)
θ = 76.0°
The resultant velocity is 103 m/s at 76.0° north of east.
