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3 years ago

What is Homogeneous?

Chemistry

2 answers:

avanturin [10]3 years ago

7 0

Answer:

A Homogeneous mixture is one that consists of a single type of element, for example - Oxygen, as it consists two oxygen atoms to make one oxygen molecule. Hope my answer helps :)

Delicious77 [7]3 years ago

6 0

Answer:

Explanation:

Hope that helps if not lmk have a wonderful day!

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In Chromium-53, the "53" represents the

alina1380 [7]

Answer:

The differemt isotopes that differ in atomic mass

Explanation:

4 0

3 years ago

Read 2 more answers

Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop

Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

Mg + Cu(NO₃)₂ ⇒ Mg(NO₃)₂ + Cu

Reactants Elements Products

1 Mg 1

1 Cu 1

2 N 2

6 O 6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

= 24 + 28 + 96

= 148 g

24 g of Mg -------------------- 148 g of Mg(NO₃)₂

147.4 g of Mg ------------------- x

x = (147.4 x 148) / 24

x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = $\frac{actual yield}{theoretical yield}$

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = $\frac{30.8}{100}$ x 908.96

Actual yield = 279.95 ≈ 280g

4 0

3 years ago

A sealed 1.0 L flask is charged with 0.500 mol of I2 and 0.500 mol of Br2. An equilibrium reaction ensues: I2 (g) + Br2 (g) ↔ 2I

Daniel [21]

Answer: Thus the value of $K_{eq}$ is 110.25

Explanation:

Initial moles of $I_2$ = 0.500 mole

Initial moles of $Br_2$ = 0.500 mole

Volume of container = 1 L

Initial concentration of $I_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M$

Initial concentration of $Br_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M$

equilibrium concentration of $IBr=\frac{moles}{volume}=\frac{0.84mole}{1L}=0.84M$ [/tex]

The given balanced equilibrium reaction is,

$I_2(g)+Br_2(g)\rightleftharpoons 2IBr(g)$

Initial conc. 0.500 M 0.500 M 0 M

At eqm. conc. (0.500-x) M (0.500-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}$

$K_c=\frac{(2x)^2}{(0.500-x)\times (0.500-x)}$

we are given : 2x = 0.84 M

x= 0.42

Now put all the given values in this expression, we get :

$K_c=\frac{(0.84)^2}{(0.500-0.42)\times (0.500-0.42)}$

$K_c=110.25$

Thus the value of the equilibrium constant is 110.25

8 0

4 years ago

A chemist determined by measurements that 0.070 moles of barium participated in a chemical reaction. Calculate the mass of bariu

34kurt

Answer: 9.59g
remember: mass = moles x Mr

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3 years ago

Identify factors that affect the ratio when substances combine to form compounds

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The law of constant proportions affects the ratio when two or more substances combine to form a new substance. The law of constant proportion, also known as Proust's law or the law of definite composition, states that a chemical compound will always have its component elements in a fixed proportion, regardless of the pathway undertaken to prepare that substance.<span />

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4 years ago