Answer:
Time observed by the astronaut = 2.388 hours
Distance traveled be according to an observer on Earth = 1.27 × 10¹¹ m
Distance traveled according to the astronaut = 2.52 × 10¹² m
Explanation:
Given:
Speed of the astronaut, v = 0.980c
time = 12.0 hr
now, from the time dilation formula we have
here
t' is the time observed by the astronaut
c is the speed of the light = 3 × 10⁸ m/s
thus,
or
t' = 2.388 hours
Now,
Distance = Velocity × time
The distance traveled be according to an observer on Earth will be
Distance = 0.980c × ( 12 × 60 × 60 )
or
D = 0.980 × 3 × 10⁸ × ( 12 × 60 × 60 )
or
Distance = 1.27 × 10¹¹ m
And, The distance traveled according to the astronaut will be
Distance = velocity × t'
or
D = 0.980 × 3 × 10⁸ × ( 2.388 × 60 × 60 )
or
Distance = 2.52 × 10¹² m
ANSWER:
The answer will be OT
Answer:
h = P₁ / 9800
Explanation:
This is a fluid mechanics problem, let's write the Bernoulli equation at two points, the subscript 1 for the lowest point and the subscript of 2 for the point with the highest height.
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂
at the highest point P₂ = 0 and v₂ = 0,
P1 + ½ ρ v12 = ρ g (y₂ -y₁)
we use the continuity equation for the velocity at the lowest point
A₁ v₁ = A₂ v₂
Since the velocity at the highest point is zero, this implies from the equation that the velocity at the lowest point is also zero. In the no-flow condition
P₁ = ρ g (y₂ -y₁)
h = y₂-y₁
h = P₁ /ρ g
the density of water is ρ = 1000 kg / m³ and g = 9.8 m/s², we substitute
h = P₁ / 9800
Let's do a calculation, suppose that P₁ = 1 10⁵ Pa
h = 1 10⁵ / 9800
h = 10.2 m
quite a lot :0
I hope this helps, and keep some kryptonite on hand dude!