Question

A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the car? (ii) what is the the distance cover ded by the car?​

Answer 1

Answer: $3.5\ km$

Explanation:

Given

Car starts from the state of rest and acquires a velocity of $70\ km/hr$ in 6 minutes

Final velocity in m/s is $v=70\approx 19.44\ m/s$

Using equation of motion

$v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2$

Distance covered in 360 s

$\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km$