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Harrizon [31]
3 years ago
9

A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the

car? (ii) what is the the distance cover ded by the car?​
Physics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer: 3.5\ km

Explanation:

Given

Car starts from the state of rest and acquires a velocity of 70\ km/hr in 6 minutes

Final velocity in m/s is v=70\approx 19.44\ m/s

Using equation of motion

v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2

Distance covered in 360 s

\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km

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Subducting convergent boundary

Explanation:

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In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​
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Explanation:

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AB || CD

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CPA = 100

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

CPA + CPD = 180 --- angle on a straight theorem

Substitute 100 for CPA

100 + CPD = 180

Subtract 100 from both sides

100-100 + CPD = 180-100

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Next, we calculate PCD

We have that:

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Subtract 136 from both sides

PCD = 180 - 136

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