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Harrizon [31]
3 years ago
9

A car starts from the state of xestIf its velocity becomes 70 km/hr in 6 minutes, i) what is the accordine acceleration of F the

car? (ii) what is the the distance cover ded by the car?​
Physics
1 answer:
Alexxandr [17]3 years ago
4 0

Answer: 3.5\ km

Explanation:

Given

Car starts from the state of rest and acquires a velocity of 70\ km/hr in 6 minutes

Final velocity in m/s is v=70\approx 19.44\ m/s

Using equation of motion

v=u+at\\\Rightarrow 19.44=0+a(6\times 60)\\\Rightarrow a=0.054\ m/s^2

Distance covered in 360 s

\Rightarrow v^2-u^2=2as\\\Rightarrow 19.44^2-0=2\times 0.054\times s\\\Rightarrow s=3500.64\ m\approx 3.5\ km

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How much heat is required to convert 500g of liquid water at 28°C into steam at 150°C? Take the specific heat capacity of water
JulijaS [17]

Answer:

1,327,063Joules

Explanation:

Heat energy is the energy needed to convert the state of a body from one phase to another.

According to the question, we want to calculate the total heat required to convert water into vapour (steam).

Note that before water can vapourize, it has to reach the boiling point first which is at 100°C. Heat energy needed to convert the water to 100°C is expressed as H1 = mcΔθ

m is the mass of the object in kg =0.5kg

c is the spcific heat capacity of water = 4183J/kg°C

Δθ is the change in temperature = 100-28 = 72°C

H1 = 0.5*4183*72

H1 = 150,588Joules

Energy required to convert the water to team H2 =mLsteam

Lsteam is the latent heat of vaporization = 2.26×10⁶J/kg

H2 = 0.5*2.26×10⁶

H2 = 1130000Joules

Heat energy needed to convert the water to 150°C is expressed as H3 = mcΔθ

m is the mass of the object in kg =0.5kg

c is the spcific heat capacity of steam= 1859J/kg°C

Δθ is the change in temperature = 150-100 = 50°C

H3 = 0.5*1859*50

H1 = 46,475Joules

Total Heat requires = H1+H2+H3 = 150,588Joules+1130000Joules+ 46,475Joules = 1,327,063Joules

8 0
3 years ago
Compare and contrast a transverse wave and a compressional wave Give an example for each type
kari74 [83]

Answer:

Transverse waves oscillate perpendicular to the direction of the wave (e.g. any electromagnetic wave like radiowaves, x-rays...) whilst compressional waves oscillate in the same direction of the wave (e.g. sound waves)

Explanation:

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3 years ago
If you put positive energy and negative energy into a spiral tube like a corkscrew with a barrier so they could not meet, so the
Aleksandr-060686 [28]

There are no rules that describe how positive energy behaves
in the presence of negative energy, because there is no such
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(Wellll ... in pop Psychology, perhaps, but not in any real science.)

3 0
3 years ago
Salmon often jump waterfalls to reach their
erik [133]

Answer:

6.35 m/s

Explanation:

The motion of the salmon is equivalent to that of a projectile, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with constant acceleration (g=-9.8 m/s^2, acceleration of gravity)

The horizontal velocity of the salmon is given by:

v_x = u cos \theta

where

u = ? is the initial speed

\theta=32^{\circ} is the angle of projection

Then the horizontal distance covered by the salmon after a time t is given by

d=v_x t =(u cos \theta) t

Or equivalently, the time taken to cover a distance d is

t=\frac{d}{u cos \theta} (1)

Along the vertical direction, the equation of motion is

h = (u sin \theta) t + \frac{1}{2}gt^2 (2)

where

u sin \theta is the initial vertical velocity

If we substitute (1) into (2), we get:

h = (u sin \theta) \frac{d}{cos \theta} + \frac{1}{2}g(\frac{d}{ ucos \theta})^2=d tan \theta + \frac{gd^2}{2u^2 cos^2 \theta}

We now that in order to reach the breeding grounds, the salmon must travel a distance of

d = 2.02 m

reaching a height of

h = 0.574 m

Substituting these data into the equation and solving for u, we find the initial speed that the salmon must have:

u =\sqrt{ \frac{gd^2}{2(h-d tan \theta) cos^2 \theta}}=\sqrt{\frac{(-9.8)(2.02)^2}{2(0.574-(2.02)(tan 32))(cos^2(32))}}=6.35 m/s

8 0
3 years ago
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Sloan [31]

Answer:

20.6 m

Explanation:

P₁ = Power of first bulb = 45 W

P₂ = Power of second bulb = 130 W

r₁ = distance from the first bulb

r₂ = distance from the second bulb = 35 m

Using the equation

\frac{P_{1}}{r_{1}^{2}} = \frac{P_{2}}{r_{2}^{2}}

Inserting the values

\frac{45}{r_{1}^{2}} = \frac{130}{35^{2}}

r₁ = 20.6 m

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