Answer:
There are several possibilities why a battery can feel hot or heat up. In case of an external short circuit: this can happen when the battery is short circuited i.e. in a purse, or in a drawer. ... Then there is also the possibility of a short circuit, forced charging and heating up the battery.
I believe your answer is C. my friend!
Answer:
3.18 Nm
Explanation:
Given that:
Radius (r) = 15cm = 15/100 = 0.15m
θ = 45°
Applied force (F) = 30 N
The Torque can be obtained using the relation :
T = rF * sinθ
T = 0.15 * 30 * sin(45)
T = 0.15 * 30 * 0.7071067
T = 3.18198015
T = 3.18 Nm
Given
m1 = 15kg
vi1 = +20 m/s
vf1 = +5 m/s
m2 = 10 kg
vi2= -15 m/s
vf2 = ?
Procedure
Conservation of momentum, general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.
![\begin{gathered} m_1v_{i1}+m_2v_{i2}=m_1v_{f2}+m_2v_{f2} \\ 15kg\cdot20m/s+10\operatorname{kg}\cdot-15m/s=15\operatorname{kg}\cdot5m/s+10\operatorname{kg}\cdot v_{f2} \\ 150-75=10v_{f2} \\ v_{f2}=75/10 \\ v_{f2}=7.5\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20m_1v_%7Bi1%7D%2Bm_2v_%7Bi2%7D%3Dm_1v_%7Bf2%7D%2Bm_2v_%7Bf2%7D%20%5C%5C%2015kg%5Ccdot20m%2Fs%2B10%5Coperatorname%7Bkg%7D%5Ccdot-15m%2Fs%3D15%5Coperatorname%7Bkg%7D%5Ccdot5m%2Fs%2B10%5Coperatorname%7Bkg%7D%5Ccdot%20v_%7Bf2%7D%20%5C%5C%20150-75%3D10v_%7Bf2%7D%20%5C%5C%20v_%7Bf2%7D%3D75%2F10%20%5C%5C%20v_%7Bf2%7D%3D7.5%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
The speed of the 10kg Ball is 7.5m/s
Answer:
The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.
Explanation:
To solve this problem we use the parabolic motion equations:
We define:
: total initial speed =![40\frac{m}{s}](https://tex.z-dn.net/?f=40%5Cfrac%7Bm%7D%7Bs%7D)
:initial speed component in vertical direction (y)
=![v_{i} sin\alpha](https://tex.z-dn.net/?f=v_%7Bi%7D%20sin%5Calpha)
: vertical speed at any point on the parabolic path
g= acceleration of gravity= 9,8 ![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
= angle that forms the total initial velocity with the ground
Equation of the speed of the football in the vertical direction :
Equation (1)
We replace
,
in the equation (1):
Equation(2)
Angle calculation
The speed of the football in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.
We replace
,
in the equation (2)
![0=(40*sin\alpha )^{2} -2*9.8*10](https://tex.z-dn.net/?f=0%3D%2840%2Asin%5Calpha%20%29%5E%7B2%7D%20-2%2A9.8%2A10)
![0=1600*(sin\alpha )^{2} -196](https://tex.z-dn.net/?f=0%3D1600%2A%28sin%5Calpha%20%29%5E%7B2%7D%20-196)
![0.1225=(sin\alpha )^{2}](https://tex.z-dn.net/?f=0.1225%3D%28sin%5Calpha%20%29%5E%7B2%7D)
![\sqrt{0.1225} =sin\alpha](https://tex.z-dn.net/?f=%5Csqrt%7B0.1225%7D%20%3Dsin%5Calpha)
![0.35=sin\alpha](https://tex.z-dn.net/?f=0.35%3Dsin%5Calpha)
°
Answer:The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.