The answer is (3) 566 K. For this problem, you need the combined gas law, which is P1V1/T1 = P2V2/T2 (variables represent Pressure, Volume, and Temperature). You are looking for T2, so you get T2 = P2V2T1/P1V1 = (38.7)(1880)(273)/(79.0)(444) = 566 K.
Answer:
Explanation:
The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleaned from the third postulate in Dalton's series. Magnesium oxide decomposes into magnesium and oxygen. If 4.03 g of magnesium oxide decomposes to form 2.43 g of magnesium, what mass of oxygen gas is also released in the reaction
The word say magnesium oxide decomposes to magnesium and oxygen
the chemical symbols say
MgO-----------> Mg + O2 (since natural oxygen is diatomic)
the balanced equation says
2MgO-------------->2Mg + O2
4.03 gm----------> 2.43 + ?0 gms
tour high school Algebra I class says
? = 4.03 -2.43 =1.60
your chemical analytcal lab says %mO in MgO = 16/40.3 = 39.7%
your calculator says
39.7/100 X 4.03 = 1.60
all of these prove the law of conservation of mass
A sound is first produced by making something VIBRATE<span>. The sound then travels through a </span><span>MEDIUM</span><span> to reach the ears, which are the parts of the body that allow for sounds to be heard.</span>
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days