Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds, double bonds, triple bonds,
and unshared pairs of electrons are on the central atom, in that order?a. 3,0,0,1b. 1,0,1,0c. 0,1,1,0d. 0,2,0,0
1 answer:
Answer:
The structure is shown below.
2,0,0,2. (There's no alternative, probably it was missing letter "e").
Explanation:
To draw the Lewis structure, we must put the central atom surrounded by the other atoms, each one with its valence electrons. The central atom is the atom that has more valence electrons.
Hydrogen has 1 valence electrons (so it does only one bond), and selenium has 6 valence electrons. So, Se does one simple bond with each hydrogen. The structure is shown below.
As we can see, there're 2 single bonds, 0 double bonds, 0 triple bonds, and 4 unshared electrons (2 pairs) in the central atom.
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0.8988
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YO_2=
now putting the values
YO_2=
=
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where
YO_2= fractional saturation of hemoglobin
pO_2= partial pressure of oxygen
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[Find the diagram in the attachment]
