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tamaranim1 [39]
2 years ago
7

Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds, double bonds, triple bonds,

and unshared pairs of electrons are on the central atom, in that order?a. 3,0,0,1b. 1,0,1,0c. 0,1,1,0d. 0,2,0,0

Chemistry
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

The structure is shown below.

2,0,0,2. (There's no alternative, probably it was missing letter "e").

Explanation:

To draw the Lewis structure, we must put the central atom surrounded by the other atoms, each one with its valence electrons. The central atom is the atom that has more valence electrons.

Hydrogen has 1 valence electrons (so it does only one bond), and selenium has 6 valence electrons. So, Se does one simple bond with each hydrogen. The structure is shown below.

As we can see, there're 2 single bonds, 0 double bonds, 0 triple bonds, and 4 unshared electrons (2 pairs) in the central atom.

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A 50.00-mL solution of 0.0350 M aniline ( Kb = 3.8 × 10–10) is titrated with a 0.0113 M solution of hydrochloric acid as the tit
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Answer:

pH = 3.70

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0.0500L × (0.0350mol / 1L) = <em>1.750x10⁻³ mol aniline</em>

Aniline is in equilibrium with water, thus:

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HCl reacts with aniline thus:

HCl + C₆H₅NH₂ → C₆H₅NH₃⁺ + Cl⁻

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C₆H₅NH₃⁺(aq) + H₂O(l) ⇄ C₆H₅NH₂(aq) + H₃O⁺(aq)

Where Ka is defined as:

Ka = [C₆H₅NH₂] [H₃O⁺] / [C₆H₅NH₃⁺] = Kw / Kb = 1.0x10⁻¹⁴ / 3.8x10⁻¹⁰ = <em>2.63x10⁻⁵ </em><em>(1)</em>

<em />

As all aniline reacts producing C₆H₅NH₃⁺, moles in equilibrium are:

[C₆H₅NH₃⁺] = 1.750x10⁻³ mol - X

[C₆H₅NH₂] = X

[H₃O⁺] = X

Replacing in (1):

2.63x10⁻⁵ =  [X] [X] / [1.750x10⁻³ mol - X]

4.6x10⁻⁸ - 2.63x10⁻⁵X = X²

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Solving for X:

X = -2.3x10⁻⁴ → False answer, there is no negative concentrations

X = 2.0x10⁻⁴ → Right answer

As [H₃O⁺] = X, [H₃O⁺] = 2.0x10⁻⁴.

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<em>pH = 3.70</em>

<em></em>

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