Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds, double bonds, triple bonds,
and unshared pairs of electrons are on the central atom, in that order?a. 3,0,0,1b. 1,0,1,0c. 0,1,1,0d. 0,2,0,0
1 answer:
Answer:
The structure is shown below.
2,0,0,2. (There's no alternative, probably it was missing letter "e").
Explanation:
To draw the Lewis structure, we must put the central atom surrounded by the other atoms, each one with its valence electrons. The central atom is the atom that has more valence electrons.
Hydrogen has 1 valence electrons (so it does only one bond), and selenium has 6 valence electrons. So, Se does one simple bond with each hydrogen. The structure is shown below.
As we can see, there're 2 single bonds, 0 double bonds, 0 triple bonds, and 4 unshared electrons (2 pairs) in the central atom.
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Answer:
D.
Explanation:
The general form of an equilibrium constant expression is
In the equilibrium
HNO₂ ⇌ H⁺ + NO₂⁻
The products are H⁺ and NO₂⁻, and the reactant is HNO₂.
∴
Answer:
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
75 % is decomposed which means that 0.75 of is decomposed. So,
= 1 - 0.75 = 0.25
t = 60 min
k = 0.023 min⁻¹
Considering the expression for half life as:-
Where, k is rate constant
So,