Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds, double bonds, triple bonds,
and unshared pairs of electrons are on the central atom, in that order?a. 3,0,0,1b. 1,0,1,0c. 0,1,1,0d. 0,2,0,0
1 answer:
Answer:
The structure is shown below.
2,0,0,2. (There's no alternative, probably it was missing letter "e").
Explanation:
To draw the Lewis structure, we must put the central atom surrounded by the other atoms, each one with its valence electrons. The central atom is the atom that has more valence electrons.
Hydrogen has 1 valence electrons (so it does only one bond), and selenium has 6 valence electrons. So, Se does one simple bond with each hydrogen. The structure is shown below.
As we can see, there're 2 single bonds, 0 double bonds, 0 triple bonds, and 4 unshared electrons (2 pairs) in the central atom.
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<h3>Further explanation</h3>Given
ΔH fusion and ΔH vaporization of different substances
Required
The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes
Solution
We can use the formula :
Q=heat/energy absorbed
n = moles
The heat absorbed : 58.16 kJ
moles = 3.11
so ΔH vaporization :
The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S
(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)