Draw the Lewis structure for the molecule containing two H and one Se atoms. How many single bonds, double bonds, triple bonds,
and unshared pairs of electrons are on the central atom, in that order?a. 3,0,0,1b. 1,0,1,0c. 0,1,1,0d. 0,2,0,0
1 answer:
Answer:
The structure is shown below.
2,0,0,2. (There's no alternative, probably it was missing letter "e").
Explanation:
To draw the Lewis structure, we must put the central atom surrounded by the other atoms, each one with its valence electrons. The central atom is the atom that has more valence electrons.
Hydrogen has 1 valence electrons (so it does only one bond), and selenium has 6 valence electrons. So, Se does one simple bond with each hydrogen. The structure is shown below.
As we can see, there're 2 single bonds, 0 double bonds, 0 triple bonds, and 4 unshared electrons (2 pairs) in the central atom.
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Answer : The correct option is, (A)
Explanation :
Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.
We can determine the van't Hoff factor by the association and dissociation of the compound.
(A)
It is an electrolyte that dissociates to give aluminum ion and chloride ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 3 = 4
(B)
It is an electrolyte that dissociates to give potassium ion and iodide ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2
(C)
It is an electrolyte that dissociates to give calcium ion and chloride ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 2 = 3
(D)
It is an electrolyte that dissociates to give magnesium ion and sulfate ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2
(E) Non-electrolyte
The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.
Hence, the highest van't Hoff factor of solute is,