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nikklg [1K]
3 years ago
8

Please help quick the 6th question is “What is a catalyst?” (include all three parts)

Chemistry
1 answer:
allochka39001 [22]3 years ago
4 0
1. The reaction is exothermic.

2. I know this because the delta H is a negative number. (-802.4 kJ)

3. This means that this reaction releases heat.
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Determine the enthalpy for this reaction: Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
ivanzaharov [21]
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol

</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
    reactants                         products

products- reactants:</span><span>

(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
<span>
</span>






6 0
2 years ago
The difference between a lamp and Tv using electrical energy
OLga [1]
Lamps heat up a coil inside a light bulb, TVs heat up tiny lamps behind liquid crystals to project a tiny image called a pixel
7 0
3 years ago
The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili
boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

  • μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

5 0
3 years ago
Nevermind i got it dont need help thanks
OverLord2011 [107]

Answer:

Ok then...

Explanation:

4 0
2 years ago
What is the formula for Dicarbon trioxide
Veronika [31]

Answer:

diboron trioxide Formula: B 2 O 3 Molecular weight: 69.620 CAS Registry Number: 1303-86-2

Explanation:

<h3><u><em>hope that helps you</em></u>╰(*°▽°*)╯</h3>
4 0
2 years ago
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