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3 years ago

If an object, initially at rest, accelerates at the rate of 25m/s2, what will the magnitude of the displacement be after 50s

Physics

1 answer:

Lady bird [3.3K]3 years ago

5 0

Answer:

31250 meters

Explanation:

Given data

Intitially at rest, the velocity will be

u= 0m/s

acceleration a= 25m/s^2

Time= 50s

We know that the expression for the displacement is given as

S=U+ 1/2at^2

S= 0+ 1/2*25*50^2

S= 12.5*2500

S=31250 meters

Hence the displacement is 31250 meters

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A boat sails south with the help of a wind blowing in the direction s36°e with magnitude 300 lb. find the work done by the wind

olga nikolaevna [1]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>Work=effective force x distance = 300cos36. 100 ft.lb.</span>

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3 years ago

An auto race takes place on a circular track. A car completes one lap in a time of 25.0 s, with an average tangential speed of 5

ludmilkaskok [199]

Answer:

(a) Angular speed will be 0.2512 rad/sec

(b) Radius will be 213.375 m

Explanation:

We have given time to complete 1 lap = 25 sec

We know that 1 lap = $2\pi$ radian

(a) So angular speed $=\frac{2\pi }{25}=\frac{2\times 3.14}{25}=0.2512rad/sec$

(B) Tangential velocity is given as v = 53.6 m/sec

We know that tangential velocity is given by

$v=\omega r$

So radius $r=\frac{v}{\omega }=\frac{53.6}{0.2512}=213.375m$

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4 years ago

True or false kinetic energy is the energy of a moving tennis ball

Kay [80]

answer = true

reasoning

kinetic energy is the energy of movement

potential energy is built up kinetic energy

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5 0

3 years ago

When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s . By how much has thermal energy increased duri

Advocard [28]

Complete question:

A fireman of mass 80 kg slides down a pole. When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s. By how much has thermal energy increased during his slide?

Answer:

The thermal energy increased by 3,099.2 J

Explanation:

Given;

mass of the fireman, m = 80 kg

initial position of the fireman, hi = 4.2 m

final speed, v = 2.2 m/s

The change in the thermal energy is calculated as;

ΔE + (K.Ef - K.Ei) + (Uf - Ui) = 0

where;

ΔE is the change in the thermal energy

K.Ef is the final kinetic energy

K.Ei is the initial kinetic energy

Uf is the final potential energy

Ui is the initial potential energy

$\Delta E_{th} + (\frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2) + (mgh_f - mgh_i)=0\\\\initial \ velocity, \ v_i = 0\\final \ height , \ h_f = o\\\\\Delta E_{th} + (\frac{1}{2} mv_f^2) + ( - mgh_i)=0\\\\\Delta E_{th} + \frac{1}{2} mv_f^2 - mgh_i = 0\\\\\Delta E_{th} =mgh_i - \frac{1}{2} mv_f^2\\\\\Delta E_{th} = 80 \times 9.8 \times 4.2 \ \ - \ \ \frac{1}{2} \times 80 \times (2.2)^2 \\\\\Delta E_{th} = 3292.8 \ J \ - \ 193.6 \ J\\\\\Delta E_{th} = 3,099.2 \ J$

3 0

3 years ago

Why do we have thunder storms

Over [174]

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3 years ago