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3 years ago

27. Calculate the impulse when an average force of 10 N acts on a cart for 5.0 s.

Physics

1 answer:

wlad13 [49]3 years ago

6 0

Answer:

50 Ns

Explanation:

Impulse = force × time

J = F Δt

J = (10 N) (5.0 s)

J = 50 Ns

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Which of the following are equivalent units?

asambeis [7]

Answer : The correct options are, (B) a newton-meter and a joule and (C) a newton and a joule/sec

Explanation :

As we know that,

$1N=1Kg\text{ m }s^{-2}\\\\1J=1\text{Kg }m^2s^{-2}\\\\1W=1\text{Kg }m^2s^{-3}$

or we can say that,

$1W=1J/s\\\\1J=1Nm\\\\1N=1J/s\\\\1W=1Nms^{-1}$

From the given options, the option B and C are the equivalent units.

Hence, the correct options are, (B) and (C)

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3 years ago

Read 2 more answers

An electric current through neon gas produces several distinct wavelengths of visible light. What are the wavelengths (in nm) of

MA_775_DIABLO [31]

Answer:

Explanation:

If a be grating element

a = 1 x 10⁻² / 11000

= .0909 x 10⁻⁵

= 909 x 10⁻⁹ m

for first order maxima , the condition is

a sinθ = λ where λ is wavelength

909 x 10⁻⁹ sin 49.67 = λ₁

λ₁ = 692.95 nm .

λ₂ = 909 x 10⁻⁹ sin 50.65

= 702.91 nm

λ₃ = 909 x 10⁻⁹ sin 52.06

= 716.88 nm

λ₄ = 909 x 10⁻⁹ sin 52.89

= 724.90 nm

692.95 nm , 702.91 nm , 716.88 nm , 724.90 nm .

4 0

3 years ago

A cylindrical tank has a radius of 53 cm and a height of 1200 mm. It weighs 9.6 kN

xxTIMURxx [149]

Answer:

1985kg

Explanation:

assuming that

pi =3.14

oil density = 950kg/ cubic meter

g= 9.8m/s

$M=\frac{9600}{9.8 } + 950 * 3.14*.53^{2} *1.2=1985kg$

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3 years ago

A star produces 2x10^26 watts. how much energy does it lose every minutes

Step2247 [10]

Answer:

Energy loss per minute will be $120\times 10^{26}j$

Explanation:

We have given the star produces power of $2\times 10^{26}W$

We know that 1 W = 1 J/sec

So $2\times 10^{26}W=2\times 10^{26}J/sec$

Given time = 1 minute = 60 sec

So the energy loss per minute $=2\times 10^{26}\times 60=120\times 10^{26}j$

We multiply with 60 we have to calculate energy loss per minute

7 0

3 years ago

An engine moves a motorboat through water at a constant velocity of 22 meters/second. If the force exerted by the motor on the b

trapecia [35]

Answer: Option B: 1.3×10⁵ W

Explanation:

$Power = \frac{Work \hspace{1mm} done}{Time}$

$P=\frac{W}{t}$

Work Done, $W= F.s$

Where s is displacement in the direction of force and F is force.

$\Rightarrow P = \frac{F.s}{t} =F \times \frac{s}{t}=F.v$

where, v is the velocity.

It is given that, F = 5.75 × 10³N

v = 22 m/s

P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W

Thus, the correct option is B

6 0

2 years ago