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3 years ago

An unbalanced force can cause an object to:

2 answers:

3 0

It'll speed up in the direction it's being pushed unbalanced. Or, it could slow down if applied the right amount of unbalanced power. And finally if the unbalanced push is pushed it could change the direction of it's current motion it was traveling.<span>
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Basile [38]3 years ago

3 0

Answer:

A. Change the direction of its velocity

B. Change the magnitude of its velocity

Explanation:

When unbalanced force is applied on a system of mass then as per Newton's II law we can say

F = ma

so we have

$a = \frac{F}{m}$

so here the system of mass will move with a given acceleration

We can define this acceleration as rate of change in velocity according to which we can say that it is either change in magnitude of speed or it is change in the direction of the speed

So correct answer would be

A. Change the direction of its velocity

B. Change the magnitude of its velocity

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Order the layers, with the oldest at the bottom and most recent at the top.

givi [52]

Answer:

adbce i think

Explanation:

7 0

3 years ago

A tiger leaps horizontally out of a tree that is 6.00 m high. If he lands 2.00 m from the base of the tree, calculate his initia

Musya8 [376]

Answer:

The initial speed of the tiger is 1.80 m/s

Explanation:

Hi there!

The equation of the position vector of the tiger is the following:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector at a time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position,

g = acceleration due to gravity.

Let´s place the origin of the frame of reference on the ground at the point where the tree is located so that the initial position vector will be:

r0 = (0.00, 6.00) m

We can use the equation of the vertical component of the position vector to obtain the time it takes the tiger to reach the ground.

y = y0 + 1/2 · g · t²

When the tiger reaches the ground, y = 0:

0 = 6.00 m - 1/2 · 9.81 m/s² · t²

2 · (-6.00 m) / -9.81 m/s² = t²

t = 1.11 s

We know that in 1.11 s the tiger travels 2.00 m in the horizontal direction. Then, using the equation of the horizontal component of the position vector we can find the initial speed:

x = x0 + v0 · t

At t = 1.11 s, x = 2.00 m

x0 = 0

2.00 m = v0 · 1.11 s

2.00 m / 1.11 s = v0

v0 = 1.80 m/s

The initial speed of the tiger is 1.80 m/s

4 0

3 years ago

How fast is Barry Allen ( The Flash) in season 5 of the Flash?

Burka [1]

Answer: The Flash, Allen's top speed is Mach 3.3, or 2,532 miles per hour.

Explanation:

8 0

3 years ago

Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O

Ann [662]

Answer:

pretty sure its studying the atomic structure of a solid carbon dioxide. so c

Explanation:

8 0

3 years ago

At a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s2

professor190 [17]

Explanation:

Given that,

Initial speed of the object, u = 1 m/s

Acceleration of the object, $a=-1\ m/s^2$

We need to find the time when the object comes at rest (v=0). Let it is given by :

$t=\dfrac{v-u}{a}$

$t=\dfrac{0-1\ m/s}{-1\ m/s^2}$

t = 1 second

So, the object will comes to rest at 1 second. Hence, this is the required solution.

5 0

3 years ago