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Oduvanchick [21]
3 years ago
12

An unbalanced force can cause an object to:

Physics
2 answers:
Lilit [14]3 years ago
3 0
It'll speed up in the direction it's being pushed unbalanced. Or, it could slow down if applied the right amount of unbalanced power. And finally if the unbalanced push is pushed it could change the direction of it's current motion it was traveling.<span>
</span>
Basile [38]3 years ago
3 0

Answer:

A. Change the direction of its velocity

B. Change the magnitude of its velocity

Explanation:

When unbalanced force is applied on a system of mass then as per Newton's II law we can say

F = ma

so we have

a = \frac{F}{m}

so here the system of mass will move with a given acceleration

We can define this acceleration as rate of change in velocity according to which we can say that it is either change in magnitude of speed or it is change in the direction of the speed

So correct answer would be

A. Change the direction of its velocity

B. Change the magnitude of its velocity

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7. Two people are pushing a 40.0kg table across the floor. Person 1 pushes with a force of 490N
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Answer:

20.4 m/s^{2}

Explanation:

To start doing this problem, first draw a free body diagram of the table. My teacher always tells us to do this, and I find that it is very helpful. I have attached a free body diagram to this answer- take a look at it.

First, let us see if Net force = MA. To do that, we need to determine whether the object is at equilibrium horizontally. For an object to be at equilibrium, it either needs to be moving at a constant velocity or not moving at all. Also, if an object is at equilibrium, there will not be any acceleration. But we know that there IS acceleration horizontally, so it cannot be in equilibrium. If it is not in equilibrium, we can use the formula ∑F= ma.

Let us determine the net force. Since the object is moving horizontally, we can ignore the weight and normal force, because they are vertical forces. The only horizontal forces we need to worry about are the applied force and force of friction.

Applied force = 1055 N (490 + 565)

Friction force= Unknown

To find the friction force, use the kinetic friction formula, Friction = μkN

μk is the coefficient, which the problem includes- it is 0.613.

N is the normal force, which we have to find.

*To find the normal force, we have to determine if the object is at equilibrium VERTICALLY. Since it has no acceleration vertically (it's not moving up/down), it is at equilibrium. Now, when an object is at equilibrium in one direction, it means that all the forces in that direction are equal. What are our vertical forces? Weight (mg) and Normal force (N). So it means that the Normal force is equal to the Weight.

Weight = mg = (40)(9.8) = 392 N

Normal force = 392 N

Now, plug it back into the formula (μkN): (0.613)(392) = 240.296 N

Friction = 240.296 N

Now that we know the friction, we can find the horizontal net force. Just subtract the friction force, 240.296 from the applied force, 1055 N

Horizontal Net Force: 814.704 N

Now that we know the net force, plug in the numbers for the formula

∑F= ma.

814.704 = (40.0)(a)

*Divide on both sides)

a = 20.3676 m/s^2

Round it to 3 significant figures, to get:

20.4 m/s^{2}

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