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ArbitrLikvidat [17]
3 years ago
9

I WILL GIVE BARINLEST WHO HELP ME3

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0

Answer:

whats the question

Step-by-step explanation:

sesenic [268]3 years ago
7 0

Answer:

What's the question

Step-by-step explanation:

???

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Which statement is true about the factorization of 30x2 + 40xy + 51y2? The polynomial can be rewritten after factoring as 10(3x2
iragen [17]

Answer:

  The greatest common factor of the terms is 1.

Step-by-step explanation:

The terms have no variables in common, and the coefficients have no factors in common. The greatest common factor of the terms is 1.

__

The discriminant is negative (40² -4(30)(51) = -4520), so any linear factors will be complex.

6 0
3 years ago
Read 2 more answers
Zoe had 1/3 bag of cookies left. She needed to share it with 2 of her friends. How much would each girl receive?
Lena [83]
1/2

(Half a cookie)



7 0
3 years ago
Find the volume v of the described solid s. the base of s is an elliptical region with boundary curve 4x2 + 9y2 = 36. cross-sect
Tasya [4]
4x^2+9y^2=36\iff\dfrac{x^2}9+\dfrac{y^2}4=1

defines an ellipse centered at (0,0) with semi-major axis length 3 and semi-minor axis length 2. The semi-major axis lies on the x-axis. So if cross sections are taken perpendicular to the x-axis, any such triangular section will have a base that is determined by the vertical distance between the lower and upper halves of the ellipse. That is, any cross section taken at x=x_0 will have a base of length

\dfrac{x^2}9+\dfrac{y^2}4=1\implies y=\pm\dfrac23\sqrt{9-x^2}
\implies \text{base}=\dfrac23\sqrt{9-{x_0}^2}-\left(-\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac43\sqrt{9-{x_0}^2}

I've attached a graphic of what a sample section would look like.

Any such isosceles triangle will have a hypotenuse that occurs in a \sqrt2:1 ratio with either of the remaining legs. So if the hypotenuse is \dfrac43\sqrt{9-{x_0}^2}, then either leg will have length \dfrac4{3\sqrt2}\sqrt{9-{x_0}^2}.

Now the legs form a similar triangle with the height of the triangle, where the legs of the larger triangle section are the hypotenuses and the height is one of the legs. This means the height of the triangular section is \dfrac4{3(\sqrt2)^2}\sqrt{9-{x_0}^2}=\dfrac23\sqrt{9-{x_0}^2}.

Finally, x_0 can be chosen from any value in -3\le x_0\le3. We're now ready to set up the integral to find the volume of the solid. The volume is the sum of the infinitely many triangular sections' areas, which are

\dfrac12\left(\dfrac43\sqrt{9-{x_0}^2}\right)\left(\dfrac23\sqrt{9-{x_0}^2}\right)=\dfrac49(9-{x_0}^2)

and so the volume would be

\displaystyle\int_{x=-3}^{x=3}\frac49(9-x^2)\,\mathrm dx
=\left(4x-\dfrac4{27}x^3\right)\bigg|_{x=-3}^{x=3}
=16

6 0
3 years ago
Please help me the tables i circles are the linear ones. Please help with them all.
Margarita [4]

Answer:

2/10

20/40

15/35

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can somebody help me please
Gre4nikov [31]

Answer:

\frac{6}{22}

Step-by-step explanation:

\frac{6}{11} × \frac{1}{2} = \frac{6*1}{11*2} = \frac{6}{22}  

7 0
4 years ago
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