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3 years ago

The activation energy for a reaction is the energy difference between what two components of a reaction?

Chemistry

1 answer:

lora16 [44]3 years ago

4 0

Answer:

Activation Energy is the Energy that Must be Overcome/reached by Reactants for Products to be formed.

I'd go with the 2nd Option.

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Name the process by which the ammonia and hydrogen Chlorade gass nove in the tube-

____ [38]

Explanation: Process is diffusion. The gas molecules follow a zig-zag path through the tube as they collide with the air molecules in the tube. The purpose of the glass tube is to eliminate air currents and to see if the gas molecules will move on their own.

I guess this helped you

I hope you would mark me as BRAINLIEST!!

8 0

3 years ago

What mass of gold is produced when 23.8 a of current are passed through a gold solution for 36.0 min ?

SVETLANKA909090 [29]

Answer:-

Solution:- The equation for the conversion of gold ions to gold metal is as follows:

$Au^3^+(aq)+3e^-\rightarrow Au(s)$

From this equation, 1 mol of Gold metal is deposited by 3 mole of electrons.

We know that one mol of electron carries one Faraday that is 96500 Coulombs.

So. 3 moles of electrons would be = 3(96500) = 289500 Coulombs

We could calculate the total Coulombs by using the formula:

q = i*t

where, q is the charge in coulombs, i is the current in ampere and t is time in seconds.

q = $23.8 ampere*36.0 min(\frac{60 sec}{1 min})$

q = 51408 ampere per second

Since, 1 ampere per second = 1 coulomb

So, 51408 ampere per second is same as 51408 coulombs.

Let's use this value of q and the info from balanced equation and molar mass(196.967 g epr mol) of gold to calculate the mass of it being deposited while the current is passed as:

$51408 coulomb(\frac{1 mol Au}{289500 coulombs})(\frac{196.967 g}{1 mol})$

= 35.0 g Au

So, 35.0 g of gold are deposited on passing 23.8 ampere of current for 36.0 min to a gold solution.

7 0

3 years ago

A real gas will deviate from the behavior of an ideal gas at ________?

Sonja [21]

B.) At higher temperature and low pressure.

Hope this helps you.

3 0

3 years ago

Determine the oxidation state of nitrogen in lino3.

Andre45 [30]

Answer : The oxidation state of nitrogen in $LiNO_3$ is, (+5)

Explanation :

Rules for the oxidation numbers :

The oxidation number of a free element is always be zero.
The oxidation number of a monatomic ion equal to the charge of the ion.
The oxidation number of Hydrogen (H) is +1.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, $LiNO_3$

Let the oxidation state of 'N' be, 'x'

$(+1)+x+3(-2)=0\\\\x=+5$

Hence, the oxidation state of N is, (+5)

3 0

4 years ago

Read 2 more answers

Please help me answer this. I am so confused.

Phoenix [80]

Same I’m so confused ‍♀️

6 0

3 years ago