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Ksivusya [100]
3 years ago
8

Number 3 help pls thank you ASAP ASAP

Mathematics
2 answers:
Ksivusya [100]3 years ago
5 0

Answer:

B

Step-by-step explanation:

babunello [35]3 years ago
5 0
The answer should be C because if you divide 57,600 by the 4000 you get 14.4 and you multiple that by the 8 which gets you 115.2 pounds of seed.
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Solve -np-80&lt;60 for n. Show your work.<br><br> Solve 2a-5d=30 for d. Show your work.
xz_007 [3.2K]

-np-80 < 60\qquad\text{change the signs}\\\\np+80

------------------------------------------------------

2a-5d=30\qquad\text{subtract 2a from both sides}\\\\-5d=-2a+30\qquad\text{change the signs}\\\\5d=2a-30\qquad\text{divide both sides by 5}\\\\d=0.4a-6

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Evaluate each expression if x = -2 and y = 3<br><br> number 34 <br><br> show step by step please!!
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How many time does 80 go into 170
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170 divided by 80 is 2.125, so 80 goes in 170, 2.125 times

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-2<br> Find the slope of the line y = 3x -<br> X – 8.
lesantik [10]

Answer:

y

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3 years ago
Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

__

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

__

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

__

4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

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3 years ago
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