<h3>
Answer: C) x = 13</h3>
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Work Shown:
We have a right triangle with legs a = 5 and b = 12. The hypotenuse is c = x which is unknown for now.
Use the pythagorean theorem to find x.
a^2 + b^2 = c^2
5^2 + 12^2 = x^2
25 + 144 = x^2
169 = x^2
x^2 = 169
x = sqrt(169) .... apply the square root to both sides
x = 13
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ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
40/100=0.4 and 72/0.4=180
so the answer is 180
Move all terms to one sides
3x^2 - 14x - 5 = 0
Split the second term in 3x^2 - 14x - 5 into two terms
3x^2 + x - 15x - 5 = 0
Factor out the common terms in the first two terms, then in the last two terms;
x(3x + 1) - 5(3x + 1) = 0
Factor out the common term 3x + 1
(3x + 1)(x - 5) = 0
Solve for x;
<u>x = -1/3, 5</u>
