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grandymaker [24]
3 years ago
13

What is science and why we use science ​

Chemistry
2 answers:
oee [108]3 years ago
5 0

Answer:

YES

Explanation:

WE use science cause it is all aaprindhs and science us everywhere .

Aleonysh [2.5K]3 years ago
4 0

Answer:

Science is the study of the universe.

Explanation:

We use it so that we can learn more about things.

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Calculate the volume in milliliters of a 5.55-g sample of a solid with a density of 3.03 g/mL
Marina86 [1]

(4.99 g) / (3.65 g/mL) = 1.37 mL

The answer to your question is 1.37ml.
8 0
3 years ago
What is the mass of one gram of calcium?
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Explanation:

The mass of one atom of calcium is the same as the molar mass of the calcium. Also, the atomic mass of calcium is 40.078 g/mol.

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2 years ago
Can radiation carry thermal energy from object to object?
Viktor [21]

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Radiation is the transfer of thermal energy by waves that can travel through empty space. When the waves reach objects, they transfer thermal energy to the objects.

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The image shows the formation of a fault-block mountain.
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5. The hanging wall on the right slides down relative to the footwall.

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A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
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