Answer:
See Explanation
Explanation:
The equation of the reaction is as follws;
4 C3H5(NO3)3 (l) → 12 CO2 (g) + 10 H2O (l) + 6 N2 (g) + O2 (g)
Number of moles of C3H5(NO3)3 = 187.4g /227 g/mol = 0.82555 moles
If 4 moles of C3H5(NO3)3 yields 12 moles of CO2
0.83 moles of C3H5(NO3)3 yields 0.82555 * 12/4 = 2.47665 moles of CO2
mass of CO2 produced = 2.47665 moles * 44 g/mol = 108.95 g of CO2
4 moles of C3H5(NO3)3 yields 10 moles of water
0.83 moles of C3H5(NO3)3 yields 0.82555 * 10/4 = 2.063875 moles of water
Mass of water = 2.063875 moles of water * 18 g/mol = 37.16 g
4 moles of C3H5(NO3)3 yields 1 mole of O2
0.83 moles of C3H5(NO3)3 yields 0.82555 * 1/4 = 0.2063875 moles of O2
Mass of O2 = 0.2063875 moles of O2 * 32 g/mol = 6.6 g
4 moles of C3H5(NO3)3 yields 6 moles of N2
0.83 moles of C3H5(NO3)3 yields 0.82555 * 6/4 = 1.238325 moles of N2
Mass of N2= 1.238325 moles of N2 * 28 g/mol = 34.67 g
To verify the law of conservation of mass, the total sum of mass of products must equal the sum of the mass of reactants. Thus;
108.95 g + 37.16 g + 6.6 g + 34.67 g = 187.4 g
The law of conservation of mass has been proven!
