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svp [43]
3 years ago
6

A car moving along a racetrack has a centripetal acceleration of 11.3 m/ s2. If the speed of the car is 30.0 m/s, what is the di

stance between the car and the center of the track?
Physics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

Explanation:

The formula for centripetal acceleration is

a_c=\frac{v^2}{r} and filling in:

11.3=\frac{(30.0)^2}{r} and solving for r:

r=\frac{(30.0)^2}{11.3} gives us that

r = 79.6 m

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What is the speed of a wave, if the wavelength is 100 m and the period is 20 s?
deff fn [24]
D. 5 m/s
This is because the formula to find the speed of a wave is the wavelength divided by the period (wavelength/period). Since the wavelength is 100 m and the period is 20 s, the speed is 5 m/s.
If you are confused on the units, then think about it this way: If you put this problem in fraction form, it would be: 100 m/20 s. 100 divided by 20 is 5, but m and s are still there. Remember that this "/" is also a division symbol. Therefore, the unit will be m/s
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4 years ago
Which statement describes the difference between ionic bonds and Van der
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Answer:

C. lonic bonds involve the transfer of electrons between ions, while

Van der Waals forces involve the attraction of nonpolar molecules.

Explanation:

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4 0
3 years ago
An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?
RoseWind [281]

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

\dfrac{\Delta L}{L}=\alpha_{l}\Delta T

\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})

Put the value into the formula

\Delta L=11\times12\times10^{-6}\times(100-20)

\Delta L=11\times12\times10^{-6}\times80

\Delta L=0.01056\ m

Hence, The change in length is 0.01056 m.

5 0
4 years ago
Which two forces exist between the protons in an atom​
r-ruslan [8.4K]

Answer: The Forces Between Protons at Nuclear Distances. Two protons are subject to two forces; the nuclear force and the electrostatic force. When they are very close together the nuclear force is dominant and when they are far apart it is the electrostatic force which is dominant.

Did that help?

8 0
3 years ago
A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera
Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
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