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svp [43]
3 years ago
6

A car moving along a racetrack has a centripetal acceleration of 11.3 m/ s2. If the speed of the car is 30.0 m/s, what is the di

stance between the car and the center of the track?
Physics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

Explanation:

The formula for centripetal acceleration is

a_c=\frac{v^2}{r} and filling in:

11.3=\frac{(30.0)^2}{r} and solving for r:

r=\frac{(30.0)^2}{11.3} gives us that

r = 79.6 m

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