If the motion of the particles in the room slow down, the temperature in the room would
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Answer:
The coefficient of kinetic friction between the puck and the ice is 0.11
Explanation:
Given;
initial speed, u = 9.3 m/s
sliding distance, S = 42 m
From equation of motion we determine the acceleration;
v² = u² + 2as
0 = (9.3)² + (2x42)a
- 84a = 86.49
a = -86.49/84
|a| = 1.0296
= ma
where;
Fk is the frictional force
μk is the coefficient of kinetic friction
N is the normal reaction = mg
μkmg = ma
μkg = a
μk = a/g
where;
g is the gravitational constant = 9.8 m/s²
μk = a/g
μk = 1.0296/9.8
μk = 0.11
Therefore, the coefficient of kinetic friction between the puck and the ice is 0.11
The new pressure P2 is 2.48 atmosphere.
<u>Explanation:</u>
Here, the one of the product of pressure and volume is equal to the products of pressure and volume of other.
By using Boyles's law,
pressure is inversely proportional to volume,
P1 V1 = P2 V2
where P1, V1 represents the first pressure and volume,
P2, V2 represents the second pressure and volume
P2 = (P1 V1) / V2
= (1.75 8.8) / 6.2
P2 = 2.48 atmosphere.