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3 years ago

How much volume (in cm3) is gained by a person who gains 12.3 lb of pure fat?

Chemistry

1 answer:

maks197457 [2]3 years ago

4 0

Answer:

So we are given with the mass while we are asked for the amount of volume. So this means, we must need an information on the density. From literature, the density of human fat is 0.918 g/cm³. Convert grams to lb by the conversion that 1,000 g = 2.2 lbs.

Density = 0.918 g/cm³ * (2.2 lbs/1,000 g) = 0.0020196 lb/cm³

Volume = Mass/Density = 12.2 lb / 0.0020196 lb/cm³

Volume = 6,040.8 cm³

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The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,

Kamila [148]

Answer: The mass percent of nitrogen gas in the compound is 13.3 %

Explanation:

Assuming the chemical equation of the compound forming product gases is:

$\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)$

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

$p_{Total}=726torr\\P_{water}=23.8torr\\$

So, pressure of nitrogen gas will be = $p_{Total}-p_{water}=726-23.8=702.2torr$

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L (Conversion factor: 1 L = 1000 mL)

T = Temperature of nitrogen gas = $25^oC=[25+273]K=298K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol$

To calculate the mass of nitrogen gas, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

$0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g$

To calculate the mass percent of nitrogen gas in compound, we use the equation:

$\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100$

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%$

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

8 0

4 years ago

10. How many grams of NH, are present in 6 moles of NH,?

LUCKY_DIMON [66]

Answer:

90.08784 grams

Explanation:

idk

3 0

3 years ago

What is the molarity of a solution with a volume of 974 mL containing 17 g of CuSO4

liberstina [14]

Answer : The correct option is, (A) 0.109 M $CuSO_4$

Solution : Given,

Mass of $CuSO_4$ = 17 g

volume of solution = 974 ml

Molar mass of $CuSO_4$ = 159.609 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{w\times 1000}{M\times V_s}$

where,

w = mass of $CuSO_4$ (solute)

M = molar mass of $CuSO_4$

$V_s$ = volume of solution in liter

Now put all the given values in the above formula, we get the molarity of solution.

$Molarity=\frac{(17g)\times 1000}{(159.609g/mole)\times (974ml)}=0.109mole/L=0.109M$

Therefore, the molarity of the solution is, 0.109 M

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4 years ago

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During which processes does the space between particles tend to increase?

ioda

Space between particles tend to increase during the application of heat or heating.

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4 years ago

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Mechanical advantage = load/_______

arlik [135]

Answer:

Mechanical advantage = load/effort

Explanation:

Mechanical advantage is like a ratio of load to effort and many machines like pulleys depend on this relationship between load and effort for it to work.

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3 years ago

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