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alexdok [17]
3 years ago
6

How high did Joseph Kittinger get up into the atmosphere before he jumped?

Chemistry
2 answers:
Trava [24]3 years ago
8 0
I know the answers I do
mamaluj [8]3 years ago
4 0

Answer:

over 50 years ago, joe kittinger rode a balloon 102,800 feet up to the edge of space. then he jumped out.

Explanation:

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kogti [31]

The piece of unknown metal is in thermal equilibrium with water such that Q of metal is equal to Q of the water. We write this equality as follows:

-Qm = Qw

Mass of metal (Cm)(ΔT) = Mass of water (Cw) (ΔT)

where C is the specific heat capacities of the materials.

We calculate as follows:

-(Mass of metal (Cm)(ΔT)) = Mass of water (Cw) (ΔT)

-68.6 (Cm)(52.1 - 100) = 42 (4.184) (52.1 - 20)

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How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100
Alona [7]

Answer:

Q = 143,921 J = 143.9 kJ.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

Q=m*\Delta _{vap}H

Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ

Regards!

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