Question

A rock is thrown horizontally out of a window with a velocity of 20.0 m/s. If the window is 8.50m above the ground, how far

Answer 1

The distance from the base of the building the rock will land is 26.4 m

Data obtained from the question

• Horizontal velocity (u) = 20 m/s
• Height (h) = 8.50 m
• Distance (s) =?

Determination of the time to reach the ground

• Height (h) = 8.50 m
• Acceleration due to gravity (g) = 9.8 m/s²
• Time (t) =?

h = ½gt²

8.5 = ½ × 9.8 × t²

8.5 = 4.9 × t²

Divide both side by 4.9

t² = 8.5 / 4.9

Take the square root of both side

t = √(8.5 / 4.9)

t = 1.32 s

How to determine the distance

• Horizontal velocity (u) = 20 m/s
• Time (t) = 1.32 s
• Distance (s) =?

s = ut

s = 20 × 1.32

s = 26.4 m

Learn more about motion under gravity:

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