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3 years ago

A rock is thrown horizontally out of a window with a velocity of 20.0 m/s. If the window is 8.50m above the ground, how far

Physics

1 answer:

vladimir1956 [14]3 years ago

6 0

The distance from the base of the building the rock will land is 26.4 m

<h3>Data obtained from the question </h3>

Horizontal velocity (u) = 20 m/s
Height (h) = 8.50 m
Distance (s) =?

<h3>Determination of the time to reach the ground </h3>

Height (h) = 8.50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?

h = ½gt²

8.5 = ½ × 9.8 × t²

8.5 = 4.9 × t²

Divide both side by 4.9

t² = 8.5 / 4.9

Take the square root of both side

t = √(8.5 / 4.9)

t = 1.32 s

<h3>How to determine the distance </h3>

Horizontal velocity (u) = 20 m/s
Time (t) = 1.32 s
Distance (s) =?

s = ut

s = 20 × 1.32

s = 26.4 m

Learn more about motion under gravity:

brainly.com/question/22719691

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