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katovenus [111]
4 years ago
15

A rock dropped into a pond produces a wave that takes 11.3 s to reach the opposite shore, 26.5 m away. the distance between cons

ecutive crests of the wave is 3 m. what is the frequency of the wave? answer in units of hz.
Physics
1 answer:
Kay [80]4 years ago
6 0
The wave takes 11.3 s to cover a distance of 26.5 m, so its speed is:
v= \frac{S}{t}= \frac{26.5 m}{11.3 s}=2.35 m/s

The distance between two consecutive crests is 3 m, and this corresponds to the wavelength of the wave. To find its frequency, we can use the relationship between the speed v, the wavelength \lambda and the frequency f:
f= \frac{v}{\lambda}= \frac{2.35 m/s}{3 m}=0.78 Hz
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The helium molecules move closer together when it's cold causing the balloon to deflate

Explanation:

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3 years ago
When comparing an x-ray to a radio wave, what should you look for to determine which formula represents the x-ray?
asambeis [7]

Answer:

D. A low lambda, λ, and a high nu, ν

Explanation:

  • Both x-rays and radio waves are electromagnetic waves that are part of the electromagnetic spectrum.
  • <em><u>Radio waves have the longest wavelengths in the electromagnetic spectrum and the lowest frequency.</u></em>
  • X-rays on the other hand <em><u>have a higher frequency compared to radio waves and a lower wavelength than that of the radio waves</u></em>.
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3 years ago
Read 2 more answers
Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe
JulijaS [17]

Answer:

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.

Explanation:

Given charges are:

\rm q_1 = +6e.\\q_2 = -6e.

The electric potential energy of a charge due to the electric field of another charge is given by

\rm EPE=\dfrac{kq_1q_2}{r}.

where,

  • k = Coulomb's constant, having value = \rm 9\times 10^9\ Nm^2/C^2.
  • r = distance between the charges.

When the charges are infinite distance apart, \rm r = \infty,

\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.

When the charges are \rm 5.61\times 10^{-12}\ m apart, \rm r=5.61\times 10^{-12}\ m,

\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.

Here, e is the charge on one electron, such that, \rm e = -1.6\times 10^{-19}\ C.

Therefore,

\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.

Thus,

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.

4 0
3 years ago
When a bat hits a baseball, what is transferred from the bat to the ball?​
GenaCL600 [577]

Answer:

kinetic energy

Explanation:

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3 years ago
You are hired to plan stunts for the next James Bond movie. In one of the film's opening scenes, Bond is going to evade some goo
kodGreya [7K]

Answer:

Explanation:

height of the building h = 15 m

initial vertical velocity u = 0

v² = u² + 2 g h

u = 0 , final velocity after falling height h

h = 15

v² = 2 x 9.8 x 15

v = 17.14 m /s

. Time of fall be t

h = 1/2 g t²

15 = 1/2 x 9.8 x t²

t = 1.749 s

This time will be required for truck to come under the building .

speed = distance / time

distance = speed x time

= 22 x 1.749

38.5 m

Truck should be at a distance of 38.5 m . when the stuntman starts falling .

5 0
3 years ago
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