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Sedaia [141]
2 years ago
7

How much energy was released if rocket hydrogen fuel was burnt ?​

Physics
2 answers:
Veseljchak [2.6K]2 years ago
7 0

Answer:

In layman's terms, burning hydrogen results in water: H2 + 1 2 O2 −→ H2O + 286, 000 joules. This combustion reaction also releases 286,000 joules of energy per mole of hydrogen gas burned.

Explanation:

suter [353]2 years ago
6 0
When ignited, the gas mixture converts to water vapor and releases energy, which sustains the reaction: 241.8 kJ of energy (LHV) for every mole of H2 burned.” A mole of hydrogen weighs 2 grams. So, this is a LHV (lower heating value) of 120.9 kJ/gram of hydrogen when heat of vaporization is subtracted.
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Please help, I need help with this test question
Arturiano [62]

I believe this is right-

for the first question, it should be fluffy

and for the second it should be spot

potential energy is unused

kinetic energy is being used

4 0
2 years ago
Which of the following correctly arranges the planets by the size of their diameter in increasing order?
Oksanka [162]

Answer:

Mercury<Venus<Earth<Mars<Jupiter< Saturn< Uranus<Neptune

6 0
2 years ago
¿A qué velocidad debe circular un auto de carreras para recorrer 87 km en 20 min? (pasar a metros por segundo m/s)
Alexxx [7]

Answer:

Velocidad en m / s = 72,25 m / s

Explanation:

Dado

Distancia a recorrer por el coche de carreras = 87 Km

1 km = 1000 m

Por lo tanto, 87 km = 87000 m

Tiempo necesario para viajar 87 km / 87000 metros = 20 minutos o 20 * 60 = 1200 segundos

Velocidad en m / s = 87000/1200

Velocidad en m / s = 72,25 m / s

7 0
3 years ago
The volume of a gas is 605 liters at 27.0°C. The new temperature is -3.0°C. What is the new volume?
nlexa [21]
From p1v1/t1 = p2v2/t2
pressure unchanged ... cancelled out
v1=605 , t1=27C = 300K,
t2=-3C = 270K
***remember temperature must be in Kelvin
we got
605/300 = v2/270
v2 = 545
5 0
3 years ago
Read 2 more answers
If a car's speed triples, how does the momentum and kinetic energy of the
Harrizon [31]

Answer: When the car speed triples, momentum also triples but Kinetic energy increases 9 times or by 9 fold.

Explanation:

The momentum of a car (an object) is

p= mv

where

m is =the mass of the object( in this case car)

v is its= velocity

While the kinetic energy is is given by the formulae

K=1/2mv²

To determine how momentum and kinetic energy of the  car changes when the speed of the object triples, We have that the new velocity,

v¹= 3v

So that  the momentum  change becomes

p¹=mv¹=m (3v)= 3mv

mv=p

therefore p¹= 3p

we can see that the momentum also triples.

And the kinetic energy change  becomes

K¹=1/2m(v¹)²= 1/2m (3v)²

= 1/2m9v²= 1/2 x m x 9 x v²=9 x1/2mv²

1/2mv²=K

K¹= Kinetic energy = 9k

but Kinetic energy increases 9 times

7 0
3 years ago
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