Question

Sulfur and oxygen can react to form both sulfur dioxide and sulfur trioxide in sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen in sulfur dioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen
a. what is the ratio of the weights of oxygen that combine with 32.06 g of sulfur ?
b. How do these data illustrate the law of multiple proportions? ​

Answer 1

Answer:

sulfur and oxygen can react to form both sulfur dioxide and sulfur trioxide in sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen in sulfur dioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen

a. what is the ratio of the weights of oxygen that combine with 32.06 g of sulfur?

b. How do these data illustrate the law of multiple proportions? ​

Explanation:

In sulfur dioxide ($SO_2$)

32.06 g of sulfur reacts with 32.0 g of oxygen.

In sulfur trioxide ($(SO_3)$ 32.0 g of sulfur reacts with 48.0 g of oxygen.

So, both th ecom[pounds are made from sulfur and oxygen,

But the amount of oxygen reacts with fixed amount of sulfur that is 32.06 g and it is in proportions that is:

32.0 g : 48.0 g

=2:3.

Hence, the ratio of oxygen combines with sulfur is in the ratio of 2:3.

b.

This data illustrates the law of multiple proportions.

Because the oxygen which is combining with fixed amount of sulfur is in proportions.

Answer 2

Answer:

Explanation:

In sulfur dioxide there are 32.06 grams of sulfur and 32 grams of oxygen .

In sulfur trioxide there are 32.06 grams of sulfur are combined with 48 grams of oxygen.

The ratio of oxygen which reacts with 32.06 gram of sulfur is 32: 48 .

This ratio is equal to 2 : 3.

This is in accordance with law of multiple proportion because , the ratio of mass of oxygen which reacts with constant mass of sulfur is integral ratio . Hence they are in accordance with law of multiple proportions.