Answer:
x<4
Step-by-step explanation:
To solve for x in the inequality equation, the terms should be rearranged such that x is on one side and integers are on the other side.
First, expand 4(x-3).
This will obtain:

Now, shift x terms and integers on each side.

After simplifying, it will get:

Finally, we can solve for x.

We can also draw the respective graph (please don't mind my drawings), where the area shaded in green is the range.
Hi!!! So to do this problem, you need to find the mean values for each sample. I will walk you through finding the mean of sample 1: first you want to add all of the values for sample 1, which are 4,5,2,4 and 3. Once you add those values you get 18. Then you must divide that 18 by the number of terms you added. The numbers you added were 4,5,2,4 and 3 like I said earlier which is 5 numbers. You divide 18 by 5 to get your mean, which is 3.6
Answer: (B) Sample 2
sample 1 mean = 3.6
sample 2 mean = 4.2
sample 3 mean = 3.8
sample 4 mean = 4
Answer:
It would be 60
Step-by-step explanation:
So 3(3*5 + 5) so 3*5 would be 15, 15+5=20, and 20*3=60
This is really simple if you can't figure this out, you might as well go back to 1st grade and below
pls try before asking
Answer:
93.39
Step-by-step explanation:
So the sum of exterior angles of the convex octagon is: 360 degrees
This means if we add all the equations that represent each angle, we can set it equal to 360 and solve for x

Group like terms

Add like terms

Now let's set the sum of exterior angles to 360

Subtract 2 from both sides

Divide both sides by 23

So by looking at all these, it appears that 6x is the highest value, given that x is positive. The way I estimated, is approximately 15.5, whenever I saw an equation like x+14, I estimated it's about 2x, since 14 is not exactly, but close to 15.5. I did this with each polynomial given. You could also manually check each one
Original equation
6x
Subsitute
6(15.565)
Simplify

We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).